Java code to Calculate average of odd and even in an array

In this tutorial, we will discuss the simple concept of the Java code to calculate the average of odd and even numbers in an array.

In this article, we are going to learn how to calculate the average of odd and even numbers in the Java programming language

What is an even or odd number?

When any integer ends in 0,2,4,6,8 and it can be divided by two with the remainder of zero, it is called as an even number.

Example of even numbers – 34,-64,78,788 – (it can be negative and positive)

When any integer ends in 0,1,3,5,7,9 and it cannot be divided without a remainder, it is called as an odd number.

Example for odd numbers – 33,-69,75,785

Here, we can use a modular operator to find odd or even number in an array

if n%2==0, n is an even number – if the number is even, the remainder is zero.

if n%2==1, n is an odd number – if the number is odd, the remainder is one.

Java code to Calculate the average of odd and even numbers using for loop

Program 1

This program allows the user to calculate the average of odd and even numbers in the given array using “for loop”.

public class OddEvenAvgArray2{
public static void main(String args[]){
int arr[]={14,43,59,68,71,86};            //1
int oddSum=0,evenSum=0,evenCount=0,oddCount=0;  //2
 
for(int i=0; i<6; i++){    //3
if(arr[i]%2==0){            //4
evenSum=evenSum+arr[i];
evenCount++;
}
else{                    //5
oddSum=oddSum+arr[i];
oddCount++;
}
}
double avgOdd=oddSum/oddCount;  //6
double avgEven=evenSum/evenCount;
System.out.println("\nAverage of even numbers are: "+avgEven);   //7
System.out.println("\nAverage of odd numbers are: "+avgOdd);
}

}

When the above code is executed, it produces the following results

Average of even numbers are:56.0
Average of odd numbers are:57.0

Method:

First, define an array with elements.
Next, declare and initialize four variables to find sum as oddSum=0, evenSum=0,oddCount=0,evenCount=0;
Then, use the “for loop” to take the elements one by one from the given array.
The “if statement” finds a number and then if the number is even, it is added to evenSum. If the number is not even, it is dealt with by “else statement”.
The “else statement” finds odd numbers and adds to oddSum.
Then, find the average of odd and even numbers
Finally, the average of odd numbers and even numbers are displayed.

Program 2

This program allows the user to choose any value for array length(Number of array elements) and input values into the array. The program will calculate the Average of odd and even numbers from the list using “for loop”.

import java.util.Scanner;
class OddEvenAvgArray3{
public static void main (String args[]){

int size,oddSum=0,evenSum=0,oddCount=0,evenCount=0;    //1
Scanner scan=new Scanner(System.in);
//create a scanner object for input

System.out.print("Enter the numbers of elements: ");
size=scan.nextInt();                                  //2

int arr[]=new int[size];                      //3
System.out.print("Enter the numbers : ");    //4
for(int i=0; i<size; i++){                     //5
arr[i]=scan.nextInt();
}
System.out.print("Enter numbers: ");
for(int i=0; i<size; i++){           //6
if(arr[i]%2==0){                     //7
evenSum=evenSum+arr[i];
evenCount++;
}
else{                         //8
oddSum=oddSum+arr[i];
oddCount++;
}

}
double avgOdd=oddSum/oddCount;     //9
double avgEven=evenSum/evenCount;
System.out.println("\nAverage of even numbers are: "+avgEven);       //10
System.out.println("\nAverage of odd numbers are: "+avgOdd);
}

}

When the above code is executed, it produces the following results

Enter the number of elements:7
Enter the numbers : 100
101
102
103
104
105
106

Average of even numbers are: 103.00
Average of odd numbers are: 103.00

Method:

To begin with , declares and initializes variables: oddSum=0, evenSum=0,ddCount=0,evenCount=0 and size.
Next, receives input from the user regarding the array length.
Then, defines an array without including the elements.
Afterwards, the elements for an array is received from the user.
Then, using the “for loop”, the elements are added one by one to the array.
Then, using the second “for loop”, elements are picked one by one from the array to determine oddness and evenness.
Next, “if statements” are used to find a number and then if it is even, it is added to evenSum.If the number is not even, it is dealt with by “else statement”.
After that, the “else statement” adds to oddSum.
Then, find the average of odd and even numbers
Finally, the average of odd numbers and even numbers are displayed.

Java code to Calculate the average of odd and even numbers using while loop

Program 1

This program allows the user to calculate the average of odd and even numbers in the given array using “while loop”.

public class OddEvenAvgArray1{
public static void main(String args[]){
int oddSum=0,evenSum=0,evenCount=0,oddCount=0;      //1
int arr[]={13,44,58,67,70,85};                    //2
int i=0; 
while(i<6){                   //3
if(arr[i]%2==0){           //4
evenSum=evenSum+arr[i];
evenCount++;
}
else{                   //5
oddSum=oddSum+arr[i];
oddCount++;
}
 i++;
}
double avgOdd=oddSum/oddCount;    //6
double avgEven=evenSum/evenCount;
System.out.println("\nSum of even numbers are:"+avgEven);     //7
System.out.println("\nSum of odd numbers are:"+avgOdd);
}
}

When the above code is executed, it produces the following results

Average of even numbers are:55.0
Average of odd numbers are:57.0

Method:

First, define an array with elements.
Next, declare and initialize variables to find sum as oddSum=0, evenSum=0 evenCount=0,oddCount=0 and size
Then, use the “while loop” to take the elements one by one from the array.
The “if statement” finds a number and then if the number is even, it is added to evenSum. If the number is not even, it is dealt with by “else statement”.
The “else statement” finds odd numbers and adds to oddSum.
Then calculate the average of odd and even numbers
Finally, the average of odd numbers and even numbers are displayed.

Program 2

import java.util.Scanner;
class OddEvenAvgArray4{
public static void main (String args[]){

int size,oddSum=0,evenSum=0,oddCount=0,evenCount=0;     //1
Scanner scan=new Scanner(System.in);
//create a scanner object for input

System.out.print("Enter the numbers of elements: ");
size=scan.nextInt();                                   //2

int arr[]=new int[size];                         //3
System.out.print("Enter the numbers : ");   //4
int i=0; 
while(i<size){                         //5
arr[i]=scan.nextInt();
 i++;
}

i=0;
while(i<size){                       //6
if(arr[i]%2==0){           //7
evenSum=evenSum+arr[i];
 evenCount++;
}
else{                           //8
oddSum=oddSum+arr[i];
oddCount++;
}
i++;
}
double avgOdd=oddSum/oddCount;         //9
double avgEven=evenSum/evenCount;
System.out.println("\nAverage of even is: "+avgOdd);      //10
System.out.println("\nAverage of odd is: "+avgEven);
}
}

When the above code is executed, it produces the following results

Enter the number of elements:7
Enter the numbers : 15
16
17
18
19
20

Average of even numbers are: 17.00
Average of odd numbers are: 18.00

Method:

To begin with , declares and initializes variables: oddSum=0, evenSum=0, evenCount=0,oddCount=0 and size.
Next, receives input from the user regarding the array length.
Then, defines an array without including the elements.
Afterwards, the elements for an array is received from the user.
Then, using the “while loop”, the elements are added one by one to the array.
Then, using the second “while loop”, elements are picked one by one from the array to determine oddness and evenness.
Next, “if statements” are used to find a number and then if it is even, it is added to evenSum. If the number is not even, it is dealt with by “else statement”.
After that, the “else statement” find odd numbers and adds to oddSum.
Then, calculate the average value of odd and even numbers
Finally, the average of odd numbers and even numbers are displayed.