C code to display Diamond number pattern

In this tutorial, we will discuss a concept of the C code to display Diamond number pattern

In this post, we will learn how to create the diamond number pattern using loops in C language.

We can use for loop, while loop or do while loop to display different diamond number patterns in C programming language.

C code to display Diamond number pattern

Here, we will use for loop to print different diamond number patterns

Program 1

Diamond pattern 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int rows;
    printf("Enter the number of rows: ");
    scanf("%d",&rows);
    int row=1,i,j,k;

for(i=rows/2; i>0; i--){    //print upper part
    for(j=1; j<=i; j++){
      printf(" ");//print space
}
for(j=1; j<=row; j++){
      printf("%d",row);
      printf(" ");
}
printf("\n");//move to next line
row++;
}

for(i=0; i<=rows/2; i++){
  for(j=1; j<=i; j++){
      printf(" ");//print space
}

for(j=row; j>=1; j--){  //print lower part
      printf("%d",row);
      printf(" ");
}
printf("\n");//move to next line
row--;
        }
    return 0;
}

When the above code is executed, it produces the following result

Enter the number of rows: 8
        1
      2   2
    3   3  3
  4   4   4  4
5   5   5   5  5
  4   4   4  4
    3   3   3
      2   2
        1

Program 2

Diamond pattern 2

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i,j,k,l,rows;
    printf("|Enter the number of rows");
    scanf("%d",&rows);
    for(i=1; i<=rows; i++){    //print upper part
    for(j=1; j<=rows-i; j++){
      printf(" ");//print initial space for upper part
}
for(k=i; k>=1; k--){
      printf("%d",k);
}
for(l=2; l<=i; l++){
      printf("%d",l);
}
printf("\n");//move to next line
}

for(i=rows-1; i>=1; i--){  //print lower part
    for(j=0; j<=rows-1-i; j++){
     printf(" ");//print initial space for lower part
}
for(k=i; k>=1; k--){
      printf("%d",k);
}
for(l=2; l<=i; l++){
      printf("%d",l);
}
printf("\n");//move to next line
        }
    return 0;
}

When the above code is executed, it produces the following result

Enter the number of rows: 6
          1
        212
      32123
    4321234
  543212345
65432123456
  543212345
    4321234
      32123
        212
          1

Program 3

Diamond pattern 3

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int rows;
    printf("Enter the number of rows: ");
    scanf("%d",&rows);
    int row=1,i,j,k;

for(i=1; i<=rows; i++){    //print upper part
    for(j=1; j<=rows-i; j++){
      printf(" ");
}
for(k=1; k<=i; k++){
      printf("%d",k);
      printf(" ");
}
printf("\n");//move to next line
}

for(i=1; i<=rows-1; i++){  //print lower part
    for(j=1; j<=i; j++){
      printf(" ");
}
for(k=1; k<=rows-i; k++){
      printf("%d",k);
      printf(" ");
}
printf("\n");//move to next line
        }
    }

When the above code is executed, it produces the following result

Enter the number of rows: 6
         1
       1  2
     1  2  3
   1  2  3  4
  1  2  3  4  5
1  2  3  4  5  6
  1  2  3  4  5
    1  2  3  4
      1  2  3 
        1  2
          1

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