• On March 7, 2019
• By Karmehavannan
• 0 Comment
• Categories: Check value
• Tags: Java language, Java programs, operator

Java program to separate even and odd numbers from an array

Java program to separate even and odd numbers from an array

In this tutorial, we will discuss the concept of the Java program to separate even and odd numbers from an array

In this post, we are going to learn how to separate the even and odd numbers from the given array.

First, we must understand how to identify odd or even number

What is Even or Odd

When the number is divided by 2 and the balance becomes zero, the above number is called as the even numbers – eg 2,4,6,8,10

and on the other sides when it is divided by 2 and balance becomes 1 they are called odd numbers or uneven numbers

In my previous post, I have explained the various approaches to check whether the  number is even or odd in Java language

 

There are three examples given below

The procedure of this program

• initially, the user will enter the size of the array and store in the variable size to define the array size
• And declare an integer type array for stored elements.
• Then the user enters all the elements of the array according to the array size.
• After that, use a loop for iterating elements of the array.
• finally, the following two  loops(for, while,do-while) separate even and odd number using the modular operator from the array.

 

Program 1

Separate even and odd numbers using for loop

The program allows the user to enter the size of the array and the array elements.

Then, it will separate the even and odd numbers from this array using for loop in Java

import java.util.Scanner;
class EvenOddArray{
public static void main (String args[]){
Scanner scan=new Scanner(System.in);
//create a scanner object for input

System.out.print("Enter the array size :\n");

int size=scan.nextInt();//reads input from user for array size
System.out.print("Enter the elements of the array :\n");

int arr[]=new int[size];

for(int i=0; i<arr.length; i++){
        arr[i]=scan.nextInt();
    }//reads input from user for array elements

    System.out.print("Even numbers are: \n");
    for(int i=0; i<size; i++){
        if(arr[i]%2==0){//separates even numbers
            System.out.println(arr[i]);
        }
    }
    
System.out.print("Odd numbers are: \n");
    for(int i=0; i<size; i++){
        if(arr[i]%2==1){//separates odd numbers
            System.out.println(arr[i]);
        }
    }
}
}

When the above code is executed, it produces the following results

Enter the array size :
8
Enter the elements of the array :
46
93
18
97
47
62
36
55

Even numbers are:
46
18
62
36

Odd  numbers are:
93
97
47
55

 

Program 2

Separate even and odd numbers using while loop

The program allows the user to enter the size of the array and the array elements.

Then, it will separate the even and odd numbers from this array using while loop in Java

import java.util.Scanner;
class EvenOddArray1{
public static void main (String args[]){
Scanner scan=new Scanner(System.in);
//create a scanner object for input

System.out.print("Enter the array size :\n");

int size=scan.nextInt();//reads input from user for array size
System.out.print("Enter the elements of the array :\n");

int arr[]=new int[size];

int i=0;
while(i<size){
        arr[i]=scan.nextInt();//reads input from user for array elements
         i++;
    }

    System.out.print("\nEven numbers are: \n"); 
i=0;
    while(i<size){
        if(arr[i]%2==0){//separate even numbers
            System.out.println(arr[i]);
             
        }
        i++;
    }
    
System.out.print("\nOdd numbers are: \n");
i=0;
    while(i<size){
        if(arr[i]%2==1){//separate odd numbers
            System.out.println(arr[i]);
             
        }
        i++;
    }
}
}

When the above code is executed, it produces the following results

Enter the array size :
6
Enter the elements of the array:
48
71
17
66
32
57

Even  numbers are:
48
66
32

Odd numbers are:
71
17
57

 

Program 3

Separate even and odd numbers using do while loop

The program allows the user to enter the size of the array and the array elements.

Then, it will separate the even and odd numbers from this array using the do-while loop in Java

import java.util.Scanner;
class EvenOddArray2{
public static void main (String args[]){
Scanner scan=new Scanner(System.in);
//create a scanner object for input

System.out.print("Enter the array size :\n");

int size=scan.nextInt();//reads input from user for array size
System.out.print("Enter the elements of the array :\n");

int arr[]=new int[size];

int i=0;
do{
        arr[i]=scan.nextInt();//reads input from user for array elements
         i++;
    }while(i<size) ;

    System.out.print("\nEven numbers are: \n"); 
i=0;
    do{
        if(arr[i]%2==0){//Separate even numbers
            System.out.println(arr[i]);
             
        }
        i++;
    }while(i<size);
    
System.out.print("\nOdd numbers are: \n");
i=0;
    do{
        if(arr[i]%2==1){//Separate odd numbers
            System.out.println(arr[i]);
             
        }
        i++;
    }while(i<size);
}
}

 

When the above code is executed, it produces the following results

Enter the array size:
6
Enter the  elements of the array:
123
234
345
456
567
678

Even numbers are:
234
456
678

Odd numbers are:
123
345
567

 

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C++ program to Separate odd and even number from an array

C program to Separate odd and even number from an array

 

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