Cpp program to display all even or odd numbers from 1 to n

Cpp program to display all even or odd numbers from 1 to n

In this tutorial, we will discuss the Cpp program to display all even or odd numbers from 1 to n

In this program, we are going to learn about how to find  odd or even number from 1 to given number using the loops in the C++ language

What is Even or Odd

When the number is divided by 2 and the balance becomes zero and the above number is called as the even number – eg 2,4,6,8,10

and on the other side when it is divided by 2 and balance becomes 1, they are called odd numbers or uneven numbers

 

In my previous post, I have explained the various approaches to check whether the  number is even or odd in C++ language

 

Once this program received the number, it will check the given number either odd or even number until the given range.

After receiving the input from the user, it is stored in the variable of num and then program divides the value of num by 2 and displays the output

 

Print all even number  using for loop

In this program, we display all even numbers from 1 to n using for loop

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Print all even numbers until\n";
    cin>>num;//reads input from the user for the maximum value
    cout<<"Even numbers from 1 to"<<num<< are\n";

    for(i=1; i<=num; i++){//loop for iterate from 1 to maximum
        if(i%2==0)//using modular operator for finding even numbers
        {
            cout<<i<<"\n";//print even number
        }
    }
getch();
    return 0;
}

When the above code is executed, it produces the following results

Print all even number till
50
Even number from 1 to 50 are
2
4
6
8
10
12
14
16
18
20
22
24
26
28
30
32
34
36
38
40
42
44
46
48
50

Print all odd number using for loop

In this program, we display all odd numbers from 1 to n using for loop

Program 2

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Print all odd numbers until\n";
    cin>>num;     //reads input from the user for the maximum value
    cout<<"Odd numbers from 1 to"<<num<< are\n";

    for(i=1; i<=num; i++){//loop for iterate from 1 to maximum
        if(i%2==1)//using modular operator for finding odd numbers
        {
            cout<<i<<"\n";
        }
    }
getch();
    return 0;
}

When the above code is executed, it produces the following results

Print all odd  number till
50
Odd number from 1 to 50 are
1
3
5
7
9
11
13
15
17
19
21
23
25
27
29
31
33
35
37
39
41
43
45
47
49

 

Print all even number using  while loop

In this program, we display all even numbers from 1 to n using while loop

Program 3

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Print all even number until\n";
    cin>>num;  //reads input from the user for the maximum value
    cout<<"Even number from 1 to"<<num<< are\n";

    i=1;
    while(i<=num){//loop for iterate from 1 to maximum
        if(i%2==0)
        {//using modular operator for finding even numbers
            cout<<i<<"\n";
        }
        i++;
    }
getch();
    return 0;
}

When the above code is executed, it produces the following results

Print all even number till
50
Even number from 1 to 50 are
2
4
6
8
10
12
14
16
18
20
22
24
26
28
30
32
34
36
38
40
42
44
46
48
50

 

Print all odd number using while loop

In this program, we display all odd numbers from 1 to n using while loop

Program 4

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Print all odd number until\n";
    cin>>num;   //reads input from the user for the maximum value
    cout<<"Odd number from 1 to"<<num<< are\n";

    i=1;
    while(i<=num){//loop for iterate from 1 to maximum
        if(i%2==1)
        {//using modular operator for finding odd numbers
            cout<<i<<"\n";
        }
        i++;
    }
getch();
    return 0;
}

 

When the above code is executed, it produces the following results

Print all odd  number till
50
Odd number from 1 to 50 are
1
3
5
7
9
11
13
15
17
19
21
23
25
27
29
31
33
35
37
39
41
43
45
47
49

 

 

Print all even number using do while loop

In this program, we display all even numbers from 1 to n using do-while loop

Program 5

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num,i;
    cout<<"Print all even  number until\n";
    cin>>num;  //reads input from the user for the maximum value
    cout<<"Even number from 1 to "<<num<<" are\n";

    i=1;
    do{//loop for iterate from 1 to maximum
        if(i%2==0)
        {//using modular operator for finding even numbers
            cout<<i<<"\n";
        }
        i++;
    }while(i<=num);
    getch();
    return 0;
}

When the above code is executed, it produces the following results

Print all even number till
50
Even number from 1 to 50 are
2
4
6
8
10
12
14
16
18
20
22
24
26
28
30
32
34
36
38
40
42
44
46
48
50

 

Print all odd number using do while loop

In this program, we display all odd numbers from 1 to n using do-while loop

Program 6

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Print all odd number until\n";
    cin>>num;  //reads input from the user for the maximum value
    cout<<"Odd number from 1 to"<<num<< "are\n";

    i=1;
    do{//loop for iterate from 1 to maximum
        if(i%2==1)
        {//using modular operator for finding odd numbers
            cout<<i<<"\n";
        }
        i++;
    }
    while(i<=num);
getch();
    return 0;
}

 

When the above code is executed, it produces the following results

Print all odd  number till
50
Odd number from 1 to 50 are
1
3
5
7
9
11
13
15
17
19
21
23
25
27
29
31
33
35
37
39
41
43
45
47
49

Suggested for you

For loop in C++ language

While loop in C++ language

Do while loop in C++ language

Operator in C++ language

Data type in C++ language

Variable in C++ language

 

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