C++ program to check odd or even using recursion

C++ program to check odd or even using recursion

In this tutorial, we will discuss a concept of the  C++ program to check odd or even  in given number using recursion

In this article, we are going to learn  how to  check of odd and even numbers using recursion in the C++ programming language

What is an even or odd number?

When any integer ends in 0,2,4,6,8 and it can be divided by two with the remainder of zero, it is called as an even number.

Example of even numbers – 34,-64,78,788

When any integer ends in 0,1,3,5,7,9 and it cannot be divided without a remainder, it is called as an odd number.

Example for odd numbers – 33,-69,75,785

Here, We can use C++ programming operators to find odd or even number in a given number

 

C++ program to check odd or even using recursion

Program 1

This program allows the user to enter a number and is used to check whether the given number is odd or even using recursion

#include <iostream>
#include <conio.h>
using namespace std;
int isEven(int);//Function prototype/ declaration
int main()
{
    int num;  
//declare a variable num
    cout << "Enter a number to find odd or even" << endl;
    cin>>num;  
//Take input from the user and stored in variable num
    if(isEven(num)){
     cout<<"It is a even number";
}
else{
     cout<<"It is a odd number";
}
cout<<endl;
getch();
    return 0;

}


int isEven(int num)//recursive function in C++
{ //function definition or function body
if(num==0){
         return 1;
}
else if(num==1){
         return 0;
}
else if(num<0){
         return isEven(-num);
}
else
return isEven(num-2);
}

When the above code is executed, it produces the following results

case 1

Enter ta number to find odd or even
345
it is a odd number

 

case 2

Enter ta number to find odd or even
456
it is a even number

 

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