Cpp program to display even and odd number in the given range

Cpp program to display even and odd number in the given range

In this tutorial, we discuss a concept of Cpp program to display even and odd number in the given range

when you devide a number by two and if the balance is zero, it is an even number

when you  divided a number by two  and if the balance is one, it is an odd number

Example of even number 2,4,6,8,…..

Example of odd number 1,3,5,7,…..

 

Here we will use a modular operator to display odd or even number in the given range.

if n%2==0,  n is a even number

if n%2==1,  n is a odd number

 

This program allows the user to enter two different digits and then, the program will display odd numbers and even numbers between entered digits using for loop

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num1, num2,r,i;

    cout<<"Enter the first number for the range: ";
    cin>>num1; //received the number for num1
    cout<<"Enter the second number for the range: ";
    cin>>num2; //received the number for num2
      cout<<"\n\nDisplay the even numbers between"<<num1 <<"and"<<num2<< "are";

    for(i=num1; i<=num2; i++){
        r=i%2;
        if(r==0)
            cout<<"\n"<<i;
    }

     cout<<"\n\nDisplay the odd numbers between"<<num1 <<"and"<<num2<< "are";

    for(i=num1; i<=num2; i++){
        r=i%2;
        if(r==1)
            cout<<"\n"<<i;
    }
    getch();
    return 0;
}

 

When the above code is executed, it produces the following results

Enter the first number for the range: 14
Enter the second number for the range: 25

Display the even numbers between 14 and 25 are
14
16
18
20
22
24

Display the odd numbers between 14 and 25 are
15
17
19
21
23
25

 

Program 2

This program allows the user to enter two different digits and then, the program will display odd numbers and even numbers between entered digits using while loop

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num1,num2,r,i;
    cout<<"Enter the first number for the range: ";
    cin>>num1;  //read first number to num1
    cout<<"Enter the second number for the range: ";
    cin>>num2;  //read second number to num2

    cout<<"\n\nDisplay even numbers between "<<num1<<" and "<<num2<<" are:";

    i=num1;
while(i<=num2){
r=i%2;
if(r==0)
cout<<"\n"<<i;
 i++;
}

cout<<"\n\nDisplay odd numbers between "<<num1<<" and "<<num2<<" are:";

i=num1;
while(i<=num2){
r=i%2;
if(r==1)
cout<<"\n"<<i;
 i++;
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the first number for the range: 12
Enter the second number for the range: 25

Display even numbers betwen 12 and 25 are:
12
14
16
18
20
22
24

Display odd numbers betwen 12 and 25 are:
13
15
17
19
21
23
25

 

Program 3

This program allows the user to enter two different digits and then, the program will display odd numbers and even numbers between entered digits using do-while loop

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num1,num2,r,i;
    cout<<"Enter the first number for the range: ";
    cin>>num1;  //read first number to num1
    cout<<"Enter the second number for the range: ";
    cin>>num2;  //read second number to num2

    cout<<"\n\nDisplay even numbers between "<<num1<<" and "<<num2<<" are:";

    i=num1;
do{
r=i%2;
if(r==0)
cout<<"\n"<<i;
 i++;
}while(i<=num2);

cout<<"\n\nDisplay odd numbers between "<<num1<<" and "<<num2<<" are:";

i=num1;
do{
r=i%2;
if(r==1)
cout<<"\n"<<i;
 i++;
}while(i<=num2);
getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the first number for the range: 27
Enter the second number for the range: 35

Display even numbers between 27 and 35 are:
28
30
32
34

Display odd numbers between 27 and 35 are:
27
29
31
33
35

 

 

Suggested for you

for loop in C++ language

While loop in C++ language

Do-while loop in C++ language

if statements in C++ language

 

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