Program to check if the given year is leap year in C++
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Program to check if the given year is leap year in C++
Program to check if the given year is leap year
In this article, we will discuss the concept of Program to check if the given year is leap year
In this post, we are going to learn how to write a program to check and display the given year is leap or not in C++ programming language.
What is leap year
leap year is occurring once every four years, which has 366 days including 29 February as an intercalary day. it is called leap year
Ex – 2000,2004.2008
Century year
The century year is ending with 00
Ex 2000, 2100, 2200
a century year may be a leap year(only if the year is exactly divisible by 400)
How to find the leap year
if The given year is perfectly divisible by 4 , it is a leap year(except century year)
only if it is perfectly divisible by 400, the century year is a leap year,
a century year should be divisible by 4 and 100 both
a non century year should be divisible only by 4
Check if the given year is leap year using if else
In this program, The program allows the user to enter the year and then it will check the given year is a leap year or not, using if – else statements in C++ language
Program 1
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int year;//variable declaration
cout<<"Enter a year for check leap or not\n";
//ask input from the user
cin>>year;
//store the input in the year variable
if ((year%400==0)||((year%4==0)&&(year%100!=0))){
cout<<year<<" is a leap year ";
}//display leap year
else{
cout<<year<<" is not a leap year ";
}
getch();
return 0;
}
When the above code is executed, it produces the following result
Case 1
Enter a year for check leap or not 2052 2052 is a leap year
Case 2
Enter a year for check leap or not 2002 2002 is not a leap year
Check if the given year is leap year using if else if
In this program, The program allows the user to enter the year and then it will check the given year is a leap year or not, using if – else if statements in C++ language
Program 2
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int year;//variable declaration
cout<<"Enter a year for check leap or not\n";
//Ask input from the user for year
cin>>year;
//store the value on the year variable
if(year%400==0){
//if it is divisible by 400
cout<<year<<" is a leap year ";
}
else if(year%100==0){
//if it is divisible by 100
cout<<year<<" is not a leap year ";
}
else if(year%4==0){
//if it is divisible by 4
cout<<year<<" is a leap year ";
}
else{
cout<<year<<" is not a leap year ";
}
getch();
return 0;
}
When the above code is executed, it produces the following result
Case 1
Enter a year for check leap or not 2000 2000 is a leap year
Case 2
Enter a year for check leap or not 2006 2006 is not a leap year
Check if the given year is leap year using Nested if
In this program, The program allows the user to enter the year and then it will check the given year is a leap year or not, using Nested if statements in C++ language
Program 3
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int year;//variable declaration
cout<<"Enter a year for check leap or not\n";
//Ask input from the user
cin>>year;
//store the input in the store variable
if(year%4==0){
if(year%100==0){
if(year%400==0){
cout<<year<<" is a leap year ";
}else
cout<<year<<" is not a leap year ";
} else
cout<<year<<" is a leap year ";
}else
cout<<year<<" is not a leap year ";
getch();
return 0;
}
When the above code is executed, it produces the following result
Case 1
Enter a year for check leap or not 2240 2240 is a leap year
Case 2
Enter a year for check leap or not 2014 2014 is not a leap year
Check if the given year is leap year using ternary operator
Here, The program allows the user to enter the year and then it will check the given year is a leap year or not, using ternary operators in C++ language
Program 4
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int year;//variable declaration
cout<<"Please Enter year for check leap: \n";
//Ask input from the user
cin>>year;//store the input in the variable year
(year%4==0 && year%100!=0)? cout<<"The entered year is a leap year":year%400==0?
cout<<"The entered year is a leap year"
:cout<<"This is not a leap year";
getch();
return 0;
}
When the above code is executed, it produces the following result
Case 1
Please Enter year for check leap or not 2024 The entered year is a leap year
Case 2
Please Enter year for check leap or not 2030 The entered year is not a leap year
Suggested post
Nested if statements in C++ language
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