Java programming code to check whether the character is Alphabet or not

In this post, we will discuss the concept of Java programming code to check whether the character is Alphabet or not

Here, we are going to learn how to find the given character is Alphabet or not in Java programming language

Java programming code to check whether the character is Alphabet or not — Alphabet or not

What is ASCII

In the Java programming language, all the character variables hold an ASCII value for computer usage.ASCII value is represented by integer values between 0 to 127.
The ASCII value of lowercase Alphabets are from 97 to 122 and The ASCII value of uppercase Alphabets are from 65 to 90

Java programming to check the character is Alphabet or not

This concept is done using three ways

using if-else statements
Using ternary operator
Using ASCII value

Programming to check the character is Alphabet or not using if-else

The program allows the user to enter a character thereafter it will check and display the result of the given character whether it is an alphabet or non-alphabet .using the if-else statements in Java language

Program 1

import java.util.Scanner;
class Check_Alphabet1{//class declaration
    
public static void main(String args[]){
char ch;//local variable
Scanner scan=new Scanner(System.in);
//takes input from the user
System.out.print("Enter a character: ");
//get input and it is stored ch variable
ch=scan.next().charAt(0);

if((ch>='A' && ch<='Z')||(ch>='a' && ch<='z')){
System.out.print(ch+" is an Alphabet: ");
}
else
{
System.out.print(ch+" is not an Alphabet: ");
}
}
}

When te above code is executed, it produces the following result

Case 1

Enter a character: S
S is an Alphabet

Case 2

Enter a character: v
v is an Alphabet

Case 3

Enter a character: 5
5 is not an Alphabet

Case 4

Enter a character: %
% is not an Alphabet

Approach

In the program, the user is asked to enter a character and entered character is stored in character variable ch
The program evaluates whether the entered character is an Alphabet or not, using if statements
If the given character is an Alphabet The program displays the output “it is an Alphabet” and if the given character is not an Alphabet it will displays “it is not an Alphabet”

Programming to check the character is Alphabet or not using ternary operator

The program allows the user to enter a character thereafter it will check and display the result of the given character whether it is an alphabet or non-alphabet .using the ternary operator in Java language

Program 2

import java.util.Scanner;
class Check_Alphabet2{//class declaration
    
public static void main(String args[]){
char ch;//local variable
Scanner scan=new Scanner(System.in);
//takes input from the user
System.out.print("Enter a character: ");
//get input and it is stored ch variable
ch=scan.next().charAt(0);

String result=((ch>='A' && ch<='Z')||(ch>='a' && ch<='z'))

? ch + " is an Alphabet"
: ch + " is not an Alphabet" ;
System.out.print(result);
}
}

When te above code is executed, it produces the following result

Case 1

Enter a character: A
A is an Alphabet

Case 2

Enter a character: e
e is an Alphabet

Case 3

Enter a character: %
% is not an Alphabet

Approach

In the program, the user is asked to enter a character and entered character is stored in character variable ch
The program evaluates whether the entered character is an Alphabet or not, using ternary operator
If the given character is an Alphabet The program displays the output “it is an Alphabet” and if the given character is not an Alphabet it will display”it is not an Alphabet”

Programming to check the character is Alphabet or not using Ascii value

The program allows the user to enter a character thereafter it will check and display the result of the given character whether it is an alphabet or non-alphabet using ASCII value in Java language

Program 3

import java.util.Scanner;
class Check_Alphabet3{//class declaration
    
public static void main(String args[]){
char ch;//local variable
Scanner scan=new Scanner(System.in);
//takes input from the user
System.out.print("Enter an character: ");
//get input and it is stored ch variable
ch=scan.next().charAt(0);


if((ch>=97 && ch<=122)||(ch>=65 && ch<=90)){
System.out.print(ch+" is an Alphabet: ");
}
else
{
System.out.print(ch+" is not an Alphabet: ");
}
}
}

When te above code is executed, it produces the following result

Case 1

Enter a character: A
A is an Alphabet

Case 2

Enter a character: s
s is an Alphabet

Case 3

Enter a character: 7
7 is not an Alphabet

Approach

In the program, the user is asked to enter a character and entered character is stored in character variable ch
The program evaluates whether the entered character is an Alphabet or not, using ASCII value
If the given character is an Alphabet The program displays the output “it is an Alphabet” and if the given character is not an Alphabet it will display”it is not an Alphabet”

The Alphabet has ASCII values between 65 to 90(capital letters) and 97 to 122 (small letters)

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