Program to Check whether an Alphabet is vowel or consonant in C++

Program to Check whether an Alphabet is a vowel or consonant in C++

In this article, we will discuss the concept of Program to Check whether an Alphabet is a vowel or consonant in C++ programming language

In this post, we are going to learn how to find whether the given alphabet is vowel or consonant in C++ language

Program to Check whether an Alphabet is vowel or consonant in C++ — Check whether vowel or not

Program to find whether an alphabet is a vowel or consonant

Program to find whether an alphabet is a vowel or consonant using if-else

Program 1

The program allows the user to enter an Alphabet thereafter it will check and display the result of the given Alphabet whether it is a vowel or consonant using the if-else statements in C++ programming language

#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
    char ch;

    cout<<"Enter an Alphabet\n";
    cin>>ch;//Takes character input from the user

          //Checking both of lower case and upper case using || (or) operator
          if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{
    cout<<ch<<" is vowel";//Display vowels
}
else{
    cout<<ch<<" is  consonant";//display consonant

}
getch();
    return 0;

}

When the above code is executed, it produces the following result

case 1

Enter an Alphabet
A
A is vowel

case 2

Enter an Alphabet
i
i is vowel

case 3

Enter an Alphabet
S
S is consonant

case 4

Enter an Alphabet
h
h is consonant

Approach

In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
The program evaluates whether the entered Alphabet is a vowel or consonant, using if-else statements
If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not vowel it will display”it is consonant”

program to find whether an Alphabet is a vowel or consonant using if-else if else

Program 2

The program allows the user to enter an Alphabet thereafter it will check and display the result of the given Alphabet whether it is a vowel or consonant using the if else-if else statements in C++ programming language

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    char ch;
    cout<<"Enter a character\n";
    cin>>ch;//Takes character input from the user
    if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{//if statements checks vowels
    cout<<ch<<" is vowel";
}
else if//else if statement checks consonant
((ch>='A' && ch<='Z')||(ch>='a' && ch<='z')){
    cout<<ch<<"  is  consonant";
}
else{
cout<<ch<<" is not an alpabet";
}
getch();
    return 0;
}

When the above code is executed, it produces the following result

case 1

Enter an Alphabet
E
E is vowel

case 2

Enter an Alphabet
u
u is vowel

case 3

Enter an Alphabet
L
L is consonant

case 4

Enter an Alphabet
h
h is consonant

Case 5

Enter an Alphabet
@
@ is not an Alphabet

Approach

In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
The program evaluates whether the entered Alphabet is a vowel or consonant, using if-else-if else statements
If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not vowel it will display”it is consonant”

program to find whether an Alphabet is a vowel or consonant using Nested if-else

Program 3

The program allows the user to enter an Alphabet thereafter it will check and display the result of the given Alphabet whether it is a vowel or consonant using the Nested if-else statements in C++ programming language

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    char ch;
    cout<<"Enter a character\n";
    cin>>ch;//Takes caracter input from the user
    if((ch>='A' && ch<='Z')||(ch>='a' && ch<='z')){ //outer if use to check consonant

    if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{//inner if statements checks vowels
    cout<<ch<<" is vowel";
}
else{//display consonant
cout<<ch<<" is consonant";
}

}
else{
cout<<ch<<" is neither a vowel nor a consonant";
}

getch();
    return 0;
}

When the above code is executed, it produces the following result

case 1

Enter an Alphabet
E
E is vowel

case 2

Enter an Alphabet
u
u is vowel

case 3

Enter an Alphabet
L
L is consonant

case 4

Enter an Alphabet
h
h is consonant

Case 5

Enter an Alphabet
@
@ is not an Alphabet

Approach

In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
The program evaluates whether the entered Alphabet is a vowel or consonant, using Nested if-else statements
If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not vowel it will display”it is consonant”

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