Java code to count even and odd numbers of an array
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Java code to count even and odd numbers of an array
Java code to count even and odd Numbers of an array
In this tutorial, we will discuss the concept of Java code to count even and odd numbers of an array
In this post, we are going to learn how to count the even and odd numbers from the given array.
First, we must understand how to identify odd and even numbers
What is Even or Odd
When the number is divided by 2 and the balance becomes zero and the above number is called as the even number – eg 2,4,6,8,10
and on the other sides when it is divided by 2 and balance becomes 1 they are called odd numbers.
In my previous post, I have explained the various approaches to check whether the number is even or odd using Java language
here, we will discuss how to count odd and even numbers from an array in Java programming language
There are three programs given below
The common procedures of these programs
- Initially, Declare an integer type array with maximum capacity(100) and declare variables i, size, odd and even
- The user will enter the size of the array and store in the variable size to define the array size
- Then, the user enters all the elements of the array according to the array size using the loop
- After that, use a loop for iterating elements of the array
- Finally, the following loops(for, while,do-while) count even and odd number using if statements from the array
Count even and odd numbers in an array using for loop
Program 1
The program allows the user to enter the size of the array and receives the elements from the user.
Then, it will count the even and odd numbers from this array using the for loop in Java
import java.util.Scanner;
class EvenOddcount{
public static void main (String args[]){
int even=0,odd=0;
Scanner scan=new Scanner(System.in);
//create a scanner object for input
System.out.print("Enter the array size :\n");
int size=scan.nextInt();//reads input from user for array size
System.out.print("Enter the elements of the array :\n");
int arr[]=new int[size];
for(int i=0; i<arr.length; i++){
System.out.printf("Enter the element arr[%d]:",i);
arr[i]=scan.nextInt();//reads input from user for array elements
}
for(int i=0; i<size; i++){
if(arr[i]%2==0){
even++;
}
else{
odd++;
}
}
System.out.println("Total even numbers of ann array: "+even);//display even numbers
System.out.println("Total even numbers of ann array: "+odd);//display odd numbers
}
}
When the above code is executed, it produces the following results
Enter the array size 10 Enter elements of the array: Enter the element arr[0] : 46 Enter the element arr[1] : 74 Enter the element arr[2] : 79 Enter the element arr[3] : 92 Enter the element arr[4] : 15 Enter the element arr[5] : 52 Enter the element arr[6] : 37 Enter the element arr[7] : 88 Enter the element arr[8] : 57 Enter the element arr[9] : 74 Total even numbers of an array :6 Total odd numbers of an array : 4
Count even and odd numbers in an array using while loop
Program 1
The program allows the user to enter the size of the array and receives the elements from the user.
Then, it will count the even and odd numbers from this array using the while loop in Java
import java.util.Scanner;
class EvenOddcount1{
public static void main (String args[]){
int even=0,odd=0;
Scanner scan=new Scanner(System.in);
//create a scanner object for input
System.out.print("Enter the array size :\n");
int size=scan.nextInt();
System.out.print("Enter the elements of the array :\n");
int arr[]=new int[size];
int i=0;
while( i<arr.length){
System.out.printf("Enter the element arr[%d]:",i);
arr[i]=scan.nextInt();
i++;
}
i=0;
while(i<size){
if(arr[i]%2==0){
even++;
}
else{
odd++;
}
i++;
}
System.out.println("Total even numbers of ann array: "+even);//display even numbers
System.out.println("Total even numbers of ann array: "+odd);//display odd numbers
}
}
When the above code is executed, it produces the following results
Enter the array size 8 Enter elements of the array: Enter the element arr[0] : 34 Enter the element arr[1] : 54 Enter the element arr[2] : 67 Enter the element arr[3] : 88 Enter the element arr[4] : 95 Enter the element arr[5] : 25 Enter the element arr[6] : 54 Enter the element arr[7] : 44 Total even numbers of an array :5 Total odd numbers of an array : 3
Count even and odd numbers in an array using the do-while loop
Program 1
The program allows the user to enter the size of the array and receives the elements from the user.
Then, it will count the even and odd numbers from this array using the do-while loop in Java
import java.util.Scanner;
class EvenOddcount2{
public static void main (String args[]){
int even=0,odd=0;
Scanner scan=new Scanner(System.in);
//create a scanner object for input
System.out.print("Enter the array size :\n");
int size=scan.nextInt();
System.out.print("Enter the elements of the array :\n");
int arr[]=new int[size];
int i=0;
do{
System.out.printf("Enter the element arr[%d]:",i);
arr[i]=scan.nextInt();
i++;
}while( i<arr.length);
i=0;
do{
if(arr[i]%2==0){
even++;
}
else{
odd++;
}
i++;
}while(i<size);
System.out.println("Total even numbers of ann array: "+even);//display even numbers
System.out.println("Total even numbers of ann array: "+odd);//display odd numbers
}
}
When the above code is executed, it produces the following results
Enter the array size 8 Enter elements of the array: Enter the element arr[0] : 567 Enter the element arr[1] : 435 Enter the element arr[2] : 788 Enter the element arr[3] : 433 Enter the element arr[4] : 466 Enter the element arr[5] : 144 Enter the element arr[6] : 567 Enter the element arr[7] : 542 Total even numbers of an array :4 Total odd numbers of an array : 4
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