In this tutorial, we will discuss The C program to calculate sum of odd and even numbers
In this article, we are going to learn the concept of how to calculate the sum of odd and even numbers in the C program
When any integer value which ends in 0,2,4,6,8 is divided by two it is called as an even number
Example for even numbers : 34,-62,58,890
When any integer value which ends in 0,1,3,5,7,9 is not divided by two it is called as an odd number
Example for odd numbers : 21,567,-57,67
We can use a modular operator to find odd or even number in the given range.
if n%2==0, n is an even number
if n%2==1, n is an odd number
Program 1
This program allows the user to enter a maximum number of digits and then, the program will sum up to odd and even numbers from 1 to entered digits using a for loop.
#include <stdio.h> #include <stdlib.h> int main() { int i, num; //declare variables i, num int oddSum=0,evenSum=0; //declare and initialize variables oddSum,evenSum printf("Enter the value of num \n"); scanf("%d",&num); for(i=1; i<=num; i++){// for loop use to iterate 1 to num if(i%2==0) //Check even number for sum evenSum=evenSum+i; else oddSum=oddSum+i; } printf("Sum of all odd numbers are: %d",oddSum); printf("\nSum of all even numbers are: %d",evenSum); getch(); return 0; }
When the above code is executed, it produces the following results
case 1
Enter the value of num: 10 Sum of all odd numbers are: 25 Sum of all even numbers are: 30
case 2
Enter the value of num: 100 Sum of all odd numbers are: 2500 Sum of all even numbers are: 2550
Program 2
This program allows the user to enter a maximum number of digits and then, the program will sum up to odd and even numbers from 1 to entered digits using a while loop.
#include <stdio.h> #include <stdlib.h> int main() { int i, num; //declare variables i, num int oddSum=0,evenSum=0; //declare and initialize variables oddSum,evenSum printf("Enter the value of num \n"); scanf("%d",&num); i=1; while(i<=num){// for loop use to iterate 1 to num if(i%2==0) //Check even number for sum evenSum=evenSum+i; else oddSum=oddSum+i; i++; } printf("Sum of all odd numbers are: %d",oddSum); printf("\nSum of all even numbers are: %d",evenSum); getch(); return 0; }
When the above code is executed, it produces the following results
case 1
Enter the value of num 12 Sum of all odd numbers are: 36 Sum of all even numbers are: 42
case 2
Enter the value of num 200 Sum of all odd numbers are: 10000 Sum of all even numbers are: 10100
Program 3
This program allows the user to enter a maximum number of digits and then, the program will sum up to odd and even numbers from 1 to entered digits using a do-while loop.
#include <stdio.h> #include <stdlib.h> int main() { int i,num; //declare variable i, num int oddSum=0,evenSum=0; //declare and initialize variables oddSum,evenSum printf("Enter the number for num\n"); scanf("%d",&num);//read the number from user i=1; do{ if(i%2==0) evenSum=evenSum+i; else oddSum=oddSum+i; i++; }while(i<=num); printf("Sum of all odd numbers are: %d ",oddSum); printf("\nSum of all even numbers are:%d ",evenSum); getch(); return 0; }
When the above code is executed, it produces the following results
case 1
Enter the value of num 150 Sum of all odd numbers are: 5625 Sum of all even numbers are: 5700
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