• On November 24, 2024
• By Karmehavannan
• 0 Comment
• Categories: Calculations, Check value
• Tags: C++ programs, Cpp language, operator

Cpp program to check whether a number is even or odd

Cpp program to check whether a number is even or odd

In this tutorial, we will discuss the Cpp program to check whether a number is even or odd

In this program, we are going to learn about how to find odd or even number from given number using if else statements in C++ programming language

What is Even or Odd

When the number is divided by 2 and the balance becomes zero. the above number is called as the even number – eg 2,4,6,8,10

and on the other sides when it is divided by 2 and balance becomes 1 there are called odd numbers or uneven numbers

Once This program received the number it will check the given number either odd or even.

After the program received input from the user, it is stored in the variable of num. then program divides the value of num into 2 and displays the output

Using modular operator

Program 1

#include 
#include 

using namespace std;

int main()
{
    int num;
    cout << "Enter a integer number: " << endl;
    cin>>num;
    if(num%2==0)
        cout<
When the above code is executed, it produces the following results
case 1
Enter an integer value: 44
44 is an even
case 2
Enter an integer value: 65
65 is an odd
when we use the modular operator, if it is the remainder appears as 0, it is called even number and if the remainder displays the balance as one, it is called as odd or uneven number
Using ternary operator
Program 2
#include 
#include 

using namespace std;

int main()
{
    int num;
    cout << "Enter an integer number: " << endl;
    cin>>num;
    (num%2==0)? cout <
 
When the above code is executed, it produces the following results
case 1
Enter an integer value: 78
78 is an even number
case 2
Enter an integer value: 99
99 is an odd number
Using Bitwise operator
Program 3
#include 
#include 
using namespace std;

int main()
{
    int num;
    cout << "Enter the integer number" << endl;
    cin>>num;

    if(num & 1)
        cout<
 
When the above code is executed, it produces the following results
case 1
Enter an integer value: 43
43 is an odd number
case 2
Enter an integer value: 68
68 is an even number
Using divisional operators
Program 4
#include 
#include 
using namespace std;

int main()
{
    int num;
    cout << "Enter the integer number" << endl;
    cin>>num;

    if((num /2)*2==num)
        cout<
 
When the above code is executed, it produces the following results
case 1
Enter an integer value: 88
88 is an even number
case 2
Enter an integer value: 47
47 is an odd number
Program 5
Using shift operators
#include 
#include 
using namespace std;

int main()
{
    int num;
    cout << "Enter the number" << endl;
    cin>>num;

    if(((num>>1)<<1)==num ){
        cout<
When the above code is executed, it produces the following results
case 1
Enter an integer value: 124
88 is even
case 2
Enter an integer value: 151
151 is odd
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