problem – C++ program to multiply two numbers without using arithmetic operator
In this tutorial, we will discuss the concept of multiplying two numbers without using arithmetic operator in C++ language.
In this post, we will learn how to get the product of two number without arithmetic operator in C++ programming language
This program is used to find the multiplication of two numbers entered by the user – using for loop without arithmetic operator
#include <iostream> #include <conio.h> using namespace std; int add(int n1, int n2); //function prototype int main() { int n1,n2,product=0,i; cout << "Enter the first number: " ; cin>>n1; cout<<"Enter first number: "; cin>>n2; for(i=0; i<n2; i++){ product=add(product,n1); //function call } cout<<"product of "<<n1<<" and "<<n2<<" is: "<<product; getch(); return 0; } int add(int num1,int num2){ //function definition int i; for(i=0; i<num2; i++) num1++; return num1; return 0; }
When the above code is executed, it produces the following result
Enter the first number: 32 Enter the second number: 5 Product of 32 and 5 is: 160
This program is used to find the multiplication of two numbers entered by the user – using while loop without arithmetic operator
#include <iostream> #include <conio.h> using namespace std; int add(int n1, int n2);//function prototype int main() { int n1,n2,product=0,i; //variable declaration cout << "Enter the first number: " ; cin>>n1; //takes input from user for n1 cout<<"Enter the second number: "; cin>>n2; //takes input from user for n2 for(i=0; i<n2; i++){ product=add(product,n1);//function call } cout<<"product of "<<n1<<" and "<<n2<<" is: "<<product; getch(); return 0; } int add(int num1,int num2){ //function definition while(num2 != 0){ int num3=(num1 & num2); num1=num1^num2; num2=num3<<1; } return num1; }
When the above code is executed, it produces the following results
Enter the first number: 22 Enter the second number: 5 Product of 32 and 5 is: 110
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