• On September 14, 2019
• By Karmehavannan
• 0 Comment
• Categories: Calculations, multiply
• Tags: C examples, C language

C program to multiply two numbers without using arithmetic operator

C program to multiply two numbers without using arithmetic operator

problem – C program to multiply two numbers without using arithmetic operator

In this tutorial, we will discuss the concept of  multiplying two numbers without using arithmetic operator in C language. 

In this post, we will learn how to get the product of two number without arithmetic operator in C programming language

C program to find the product of two numbers

Using for loop – Program 1

This program is used to find the multiplication of two numbers entered by the user – using for loop without arithmetic operator

#include <stdio.h>
#include <stdlib.h>
int add(int n1, int n2);

int main()
{
    int n1,n2,product=0,i;//variable declaration
    printf("Enter the first  number: ");
    scanf("%d",&n1);  //Takes input from the user for n1
    printf("Enter the first  number: ");
    scanf("%d",&n2);   //Takes input from the user for n2
    for(i=0; i<n2; i++){
    product=add(product,n1);
}
printf("product of %d and %d are: %d\n",n1,n2,product);
    getch();
    return 0;
}

int add(int num1,int num2){
    int i;
for(i=0; i<num2; i++)
   num1++;
return num1;
}

When the above code is executed, it produces the following results

Enter the first number: 12
Enter the second number:23
product of 12 and 23 are: 276

Using while loop – Program 2

This program is used to find the multiplication of two numbers entered by the user – using while loop without arithmetic operator

#include <stdio.h>
#include <stdlib.h>
int add(int n1, int n2);

int main()
{
    int n1,n2,product=0,i;
    printf("Enter first  number: ");
    scanf("%d",&n1);  //Takes input from the user for n1
    printf("Enter first  number: ");
    scanf("%d",&n2);   //Takes input from the user for n2
    for(i=0; i<n2; i++){
    product=add(product,n1);
}
printf("product of %d and %d is: %d\n",n1,n2,product);
    getch();
    return 0;
}

int add(int num1,int num2){
    while(num2 != 0){
int num3=(num1 & num2);
num1=num1^num2;
num2=num3<<1;

}
return num1;
}

When the above code is executed, it produces the following results

Enter the first number: 12
Enter the second number:24
product of 12 and 23 are: 288

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