problem – C program to multiply two numbers without using arithmetic operator
In this tutorial, we will discuss the concept of multiplying two numbers without using arithmetic operator in C language.
In this post, we will learn how to get the product of two number without arithmetic operator in C programming language
This program is used to find the multiplication of two numbers entered by the user – using for loop without arithmetic operator
#include <stdio.h> #include <stdlib.h> int add(int n1, int n2); int main() { int n1,n2,product=0,i;//variable declaration printf("Enter the first number: "); scanf("%d",&n1); //Takes input from the user for n1 printf("Enter the first number: "); scanf("%d",&n2); //Takes input from the user for n2 for(i=0; i<n2; i++){ product=add(product,n1); } printf("product of %d and %d are: %d\n",n1,n2,product); getch(); return 0; } int add(int num1,int num2){ int i; for(i=0; i<num2; i++) num1++; return num1; }
When the above code is executed, it produces the following results
Enter the first number: 12 Enter the second number:23 product of 12 and 23 are: 276
This program is used to find the multiplication of two numbers entered by the user – using while loop without arithmetic operator
#include <stdio.h> #include <stdlib.h> int add(int n1, int n2); int main() { int n1,n2,product=0,i; printf("Enter first number: "); scanf("%d",&n1); //Takes input from the user for n1 printf("Enter first number: "); scanf("%d",&n2); //Takes input from the user for n2 for(i=0; i<n2; i++){ product=add(product,n1); } printf("product of %d and %d is: %d\n",n1,n2,product); getch(); return 0; } int add(int num1,int num2){ while(num2 != 0){ int num3=(num1 & num2); num1=num1^num2; num2=num3<<1; } return num1; }
When the above code is executed, it produces the following results
Enter the first number: 12 Enter the second number:24 product of 12 and 23 are: 288
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