C program to count vowels and consonants in a string

In this article, we will discuss the concept of C program to count vowels and consonants in a string

In this post, we are going to learn how to count the vowels and consonants in the given string in C programming language

C program to count vowels or consonants of the given string — count vowels and consonant

Code to count the vowels and consonants using for loop

The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using for loop in C language

Program 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];//declara a char array
    int i,vowCount=0,consCount=0;//declare counter variables
    printf("Enter a string for count vowel and consonant\n");
    gets(str);
    for(i=0; str[i]; i++){
        if(str[i] == 'a'|| str[i] == 'e'|| str[i] == 'i'|| str[i] == 'o'|| str[i] == 'u'
    ||str[i] == 'A'|| str[i] == 'E'|| str[i] == 'I'|| str[i] == 'O'|| str[i] == 'U' ){
        vowCount++;
    }
    else if((str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z' )){
        consCount++;
    }
}
printf("The number of vowels: %d \n",vowCount);
printf("The number of consonant: %d \n",consCount);
getch();
    return 0;
}

When the above code is executed, it produces the following result

Enter a string for count vowel and consonant
Vowels
The number of vowels: 2
The number of vowels: 4

Approach

Declare a string using character Array as char str[100];
Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
The user asked to enter a string to count vowels and consonants
A for-loop is used to count total vowels and consonants of the given string
It is initialized as i=0, and checks the test-expression and executes the loop until the given condition becomes true
Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
When the if-condition is false, control moves to else if and checks the test expression of else-if
If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
If the test expression of else-if is false, control skips from the loop
Finally, the program displays the number of vowels and consonants of the given string.

C program to count vowel and consonant using while loop

The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using while loop in C language

Program 2

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];//declare a character array
    int i,vowCount=0,consCount=0;//declare counter variables
    printf("Enter a string for count vowel and consonant\n");
    gets(str);//store the string input from the user
    i=0;
    while(str[i]){
        if(str[i] == 'a'|| str[i] == 'e'|| str[i] == 'i'|| str[i] == 'o'|| str[i] == 'u'
    ||str[i] == 'A'|| str[i] == 'E'|| str[i] == 'I'|| str[i] == 'O'|| str[i] == 'U' ){
        vowCount++;
    }
    else if((str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z' )){
        consCount++;
    }
     i++;
}
printf("The number of vowels: %d \n",vowCount);
printf("The number of consonant: %d \n",consCount);
getch();
    return 0;
}

When the above code is executed, it produces the following result

Enter a string for count vowel and consonant
Vowel and consonant
The number of vowels: 6
The number of vowels: 11

Approach

Declare a character Array as char str[100];
Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
The user asked to enter a string to count vowels and consonants
A while-loop is used to count total vowels and consonants of the given string
It is initialized as i=0, and checks the test expression and executes the loop until the given condition becomes true
Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
When the if-condition is false, control moves to else-if and checks the test expression of else-if
If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
If the test expression of else-if is false, control skips from the loop
Finally, the program displays the number of vowels and consonants of the given string.

C program to count vowel and consonant using do-while loop

The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using do-while loop in C language

Program 3

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];
    int i,vowCount=0,consCount=0;
    printf("Enter a string for count vowel and consonant\n");
    gets(str);
    i=0;
    do{
        if(str[i] == 'a'|| str[i] == 'e'|| str[i] == 'i'|| str[i] == 'o'|| str[i] == 'u'
    ||str[i] == 'A'|| str[i] == 'E'|| str[i] == 'I'|| str[i] == 'O'|| str[i] == 'U' ){
        vowCount++;
    }
    else if((str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z' )){
        consCount++;
    }
     i++;
}while(str[i]);
printf("The number of vowels: %d \n",vowCount);
printf("The number of consonant: %d \n",consCount);
getch();
    return 0;
}

When the above code is executed, it produces the following result

Enter a string for count vowel and consonant
Alphabet letters
The number of vowels: 5
The number of vowels: 10

Approach

Declare a character Array as char str[100];
Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
The user asked to enter a string to count vowels and consonants
A do-while loop is used to count total vowels and consonants of the given string
It is initialized as i=0, and checks the test-expression and executes the loop until the given condition becomes true
Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
When the if-statement is false, control moves to else-if and checks the test expression of else-if
If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
If the test expression of else-if is false, control skips from the loop
Finally, the program displays the number of vowels and consonants of the given string.