C++ Program for count upper or lowercase letter of the given string

In this article, we will discuss the concept of the C++ Program to count uppercase or lowercase letter of the given string

In this post, we are going to learn how to count upper and lower case letters in a given string in C++ programming language

C++ Program for count upper or lowercase letter of the given string

Code for count upper or lowercase letter using for loop

Program 1

#include <iostream>
#include <stdio.h>
#include <conio.h>
using namespace std;

int main()
{
    int i;
    int upper=0,lower=0;//variable declaration
    char ch[100];//array declaration

    cout<<"Enter the String:\n";
    gets(ch);

    for(i=0; ch[i]!=0; i++){

if(ch[i]>='A' && ch[i]<='Z'){
    upper++;
}
else if(ch[i]>='a' && ch[i]<='z'){
    lower++;
}
    }
cout<<"lowercase letters:" <<lower;
cout<<"\nuppercase letters:"<<upper;
getch();
    return 0;
}

When the above code is executed, it produces the following result

Enter the string:
CPP Language
lowercase letters:7
uppercase letters:4

Approach

Declare a variable as int i;
Declare and initialize two integer counter-variable as int upper=0 and lower=0;
Declare a character Array as char ch[100];
The user asked to enter a string to count upper case and lower case letters
A for-loop is used to count total upper case and lower case of the given string
It is initialized as i=0, and checks condition whether ch[i]!=0;, and executes the loop until the given condition becomes true
Use an if statement to test upper case, if the test expression is true, upper becomes upper + 1 (upper=upper+1)
When the if-statements is false, The control moves to else if and checks the test expression of else-if
If the test expression of else-if is true, lower becomes lower + 1(lower =lower +1)
If the test expression of else if is false, control terminates from the loop
Finally, the program displays the number of upper case and lowercase letters of the given string.

Code for count upper or lowercase letter using while loop

The program allows to enter a String and it counts and displays whether the number of upper case and lower case letters of the given string using while loop in C++ language

Program 2

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;

int main()
{
    int i;
    int upper=0,lower=0;
    char ch[100];

    cout<<"Enter the String:\n";
    gets(ch);

    i=0;
    while(ch[i]!=0){

if(ch[i]>='A' && ch[i]<='Z'){
    upper++;
}
else if(ch[i]>='a' && ch[i]<='z'){
    lower++;
}
i++;
    }
cout<<"lowercase letters: "<<lower;
cout<<"\nuppercase letters: "<<upper;
getch();
    return 0;
}

When the above code is executed, it produces the following result

Enter the string:
Count Upper Lower
lowercase letters:12
uppercase letters:3

Approach

Declare a variable as int i;
Declare and initialize two integer counter-variable as int upper=0 and lower=0;
Declare a character Array as char ch[100];
The user asked to enter a string to count upper case and lower case letters
A while-loop is used to count total upper case and lower case of the given string
It is initialized as i=0, and checks condition whether ch[i]!=0;, and executes the loop until the given condition becomes true
Use an if statement to test upper case, if the test expression is true, upper becomes upper + 1 (upper=upper+1)
When the if-statements is false, The control moves to else if and checks the test expression of else-if
If the test expression of else-if is true, lower becomes lower + 1(lower =lower +1)
If the test expression of else if is false, control terminates from the loop
Finally, the program displays the number of upper case and lowercase letters of the given string.

Code for count upper or lowercase letter using do-while loop

The program allows to enter a String and it counts and displays whether the number of upper case and lower case letters of the given string using do-while loop in C++ language

Program 3

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;

int main()
{
    int i;
    int upper=0,lower=0;
    char ch[100];

    cout<<"Enter the String:\n";
    gets(ch);

    i=0;
   do{

if(ch[i]>='A' && ch[i]<='Z'){
    upper++;
}
else if(ch[i]>='a' && ch[i]<='z'){
    lower++;
}
i++;
    } while(ch[i]!=0);
cout<<"lowercase letters: "<<lower;
cout<<"\nuppercase letters: "<<upper;
getch();
    return 0;
}

When the above code is executed, it produces the following result

Enter the string:
UpperCase and LowerCase
lowercase letters:12
uppercase letters:3

Approach

Declare a variable as int i;
Declare and initialize two integer counter-variable as int upper=0 and lower=0;
Declare a character Array as char ch[100];
The user asked to enter a string to count upper case and lower case letters
A while-loop is used to count total upper case and lower case of the given string
It is initialized as i=0, and checks condition whether ch[i]!=0;, and executes the loop until the given condition becomes true
Use an if statement to test upper case, if the test expression is true, upper becomes upper + 1 (upper=upper+1)
When the if-statements is false, The control moves to else if and checks the test expression of else-if
If the test expression of else-if is true, lower becomes lower + 1(lower =lower +1)
If the test expression of else if is false, control terminates from the loop
Finally, the program displays the number of upper case and lowercase letters of the given string.