C Program for count upper or lowercase letter of the given string
C Program for count upper or lowercase letter of the given string
In this article, we will discuss the concept of the C Program for count upper or lowercase letter of the given string
In this post, we are going to learn how to count upper and lower case letters in a given string in C programming language
Program to count upper or lowercase letter using for loop
The program allows to enter a String and then it counts and displays whether the number of upper case and lower case letters of the given string using for loop in C language
Program 1
#include <stdio.h> #include <stdlib.h> int main() { int i; int upper=0,lower=0; char ch[100]; printf("Enter the String:\n"); gets(ch); for(i=0; ch[i]!=0; i++){ if(ch[i]>='A' && ch[i]<='Z'){ upper++; } else if(ch[i]>='a' && ch[i]<='z'){ lower++; } } printf("lowercase letters: %d",lower); printf("\nuppercase letters: %d",upper); getch(); return 0; }
When the above code is executed, It produces the following result
Enter the String C language lowercase letters: 7 uppercase letters:2
Approach
- Declare a variable as int i;
- Declare and initialize two integer counter-variable as int upper=0 and lower=0;
- Declare a character Array as char ch[100];
- The user asked to enter a string to count upper case and lower case letters
- A for-loop is used to count total upper case and lower case of the given string
- It is initialized as i=0, and checks condition whether ch[i]!=0;, and executes the loop until the given condition becomes true
- Use an if statement to test upper case, if the test expression is true, upper becomes upper + 1 (upper=upper+1)
- When the if-statements is false, The control moves to else if and checks the test expression of else-if
- If the test expression of else-if is true, lower becomes lower + 1(lower =lower +1)
- If the test expression of else if is false, control terminates from the loop
- Finally, the program displays the number of upper case and lowercase letters of the given string.
Code to count upper or lowercase letter using while loop
The program allows to enter a String and it counts and displays whether the number of upper case and lower case letters of the given string using while loop in C language
Program 2
#include <stdio.h> #include <stdlib.h> int main() { int i; int upper=0,lower=0; char ch[100]; printf("Enter the String:\n"); gets(ch); i=0; while(ch[i]!=0){ if(ch[i]>='A' && ch[i]<='Z'){ upper++; } else if(ch[i]>='a' && ch[i]<='z'){ lower++; } i++; } printf("lowercase letters: %d",lower); printf("\nuppercase letters: %d",upper); getch(); return 0; }
When the above code is executed, It produces the following result
Enter the String C Program for Upper Lower lowercase letters: 17 uppercase letters:7
Approach
- Declare a variable as int i;
- Declare and initialize two integer counter-variable as int upper=0 and lower=0;
- Declare a character Array as char ch[100];
- The user asked to enter a string to count upper case and lower case letters
- A while-loop is used to count total upper case and lower case of the given string
- It is initialized as i=0, and checks condition whether ch[i]!=0;, and executes the loop until the given condition becomes true
- Use an if statement to test upper case, if the test expression is true, upper becomes upper + 1 (upper=upper+1)
- When the if-statements is false, The control moves to else if and checks the test expression of else-if
- If the test expression of else-if is true, lower becomes lower + 1(lower =lower +1)
- If the test expression of else if is false, control terminates from the loop
- Finally, the program displays the number of upper case and lowercase letters of the given string.
Code to count upper or lowercase letter using do-while loop
The program allows to enter a String and it counts and displays whether the number of upper case and lower case letters of the given string using do-while loop in C language
Program 3
#include <stdio.h> #include <stdlib.h> int main() { int i; int upper=0,lower=0; char ch[100]; printf("Enter the String:\n"); gets(ch); i=0; do{ if(ch[i]>='A' && ch[i]<='Z'){ upper++; } else if(ch[i]>='a' && ch[i]<='z'){ lower++; } i++; }while(ch[i]!=0); printf("lowercase letters: %d",lower); printf("\nuppercase letters: %d",upper); getch(); return 0; }
When the above code is executed, It produces the following result
Enter the String C is a procedural language lowercase letters: 19 uppercase letters:3
Approach
- Declare a variable as int i;
- Declare and initialize two integer counter-variable as int upper=0 and lower=0;
- Declare a character Array as char ch[100];
- The user asked to enter a string to count upper case and lower case letters
- A do-while-loop is used to count total upper case and lower case of the given string
- It is initialized as i=0, and checks condition whether ch[i]!=0;, and executes the loop until the given condition becomes true
- Use an if statement to test upper case, if the test expression is true, upper becomes upper + 1 (upper=upper+1)
- When the if-statements is false, The control moves to else if and checks the test expression of else-if
- If the test expression of else-if is true, lower becomes lower + 1(lower =lower +1)
- If the test expression of else if is false, control terminates from the loop
- Finally, the program displays the number of upper case and lowercase letters of the given string.
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