C code to display Diamond number pattern
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C code to display Diamond number pattern
C code to display Diamond number pattern
In this tutorial, we will discuss a concept of the C code to display Diamond number pattern
In this post, we will learn how to create the diamond number pattern using loops in C language.
We can use for loop, while loop or do while loop to display different diamond number patterns in C programming language.

Here, we will use for loop to print different diamond number patterns
Program 1
Diamond pattern 1
#include#include int main() { int rows; printf("Enter the number of rows: "); scanf("%d",&rows); int row=1,i,j,k; for(i=rows/2; i>0; i--){ //print upper part for(j=1; j<=i; j++){ printf(" ");//print space } for(j=1; j<=row; j++){ printf("%d",row); printf(" "); } printf("\n");//move to next line row++; } for(i=0; i<=rows/2; i++){ for(j=1; j<=i; j++){ printf(" ");//print space } for(j=row; j>=1; j--){ //print lower part printf("%d",row); printf(" "); } printf("\n");//move to next line row--; } return 0; }
When the above code is executed, it produces the following result
Enter the number of rows: 8
1
2 2
3 3 3
4 4 4 4
5 5 5 5 5
4 4 4 4
3 3 3
2 2
1Program 2
Diamond pattern 2
#include#include int main() { int i,j,k,l,rows; printf("|Enter the number of rows"); scanf("%d",&rows); for(i=1; i<=rows; i++){ //print upper part for(j=1; j<=rows-i; j++){ printf(" ");//print initial space for upper part } for(k=i; k>=1; k--){ printf("%d",k); } for(l=2; l<=i; l++){ printf("%d",l); } printf("\n");//move to next line } for(i=rows-1; i>=1; i--){ //print lower part for(j=0; j<=rows-1-i; j++){ printf(" ");//print initial space for lower part } for(k=i; k>=1; k--){ printf("%d",k); } for(l=2; l<=i; l++){ printf("%d",l); } printf("\n");//move to next line } return 0; }
When the above code is executed, it produces the following result
Enter the number of rows: 6
1
212
32123
4321234
543212345
65432123456
543212345
4321234
32123
212
1Program 3
Diamond pattern 3
#include#include int main() { int rows; printf("Enter the number of rows: "); scanf("%d",&rows); int row=1,i,j,k; for(i=1; i<=rows; i++){ //print upper part for(j=1; j<=rows-i; j++){ printf(" "); } for(k=1; k<=i; k++){ printf("%d",k); printf(" "); } printf("\n");//move to next line } for(i=1; i<=rows-1; i++){ //print lower part for(j=1; j<=i; j++){ printf(" "); } for(k=1; k<=rows-i; k++){ printf("%d",k); printf(" "); } printf("\n");//move to next line } }
When the above code is executed, it produces the following result
Enter the number of rows: 6
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6
1 2 3 4 5
1 2 3 4
1 2 3
1 2
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