Python Program to check leap year
In this article, we will discuss the concept of Python Program to find leap year
In this post, we are going to learn how to write a program to check and display the given year is leap or not in Python programming language.
What is leap year
leap year is occurring once every four years, which has 366 days including 29 February as an intercalary day. it is called leap year
Ex – 2000,2004.2008
Century year
The century year is ending with 00
Ex 2000, 2100, 2200
a century year may be a leap year(only if the year is exactly divisible by 400)
Code to check leap year
How to find the leap year
if The given year is perfectly divisible by 4 , it is a leap year(except century year)
the century year is a leap year, only it is perfectly divisible by 400..
a century year should be divisible by 4 and 100 both
a non century year should be divisible only by 4
Check if the given year is leap year using if else
Here, The program allows the user to enter the year and then it will check the given year is a leap year or not, using if – else statements in Python language
Program 1
#Python program to check leap year using if statements
year=int(input("Please enter the year you wish: "));
if ((year%400==0)or((year%4==0)and(year%100!=0))):
#if it is true display leap year
#if it is false move to else part
print("%d is a leap year"%year);
else:
print("%d is not a leap year"%year);
When the above code is executed, it produces the following result
Case 1
Please enter the year you wish: 2224 2224 is a leap year
Case 2
Please enter the year you wish: 2222 2222 is not a leap year
Check if the given year is leap year using if elif else
Here, The program allows the user to enter the year and then it will check the given year is a leap year or not, using if – elif elae statements in Python language
Program 2
#Python program to check leap year using elif statements
year=int(input("Please enter the year for check leap or not: "))
#Ask input from the user and store the value in the year variable
if(year%400==0):
#if the year id divided by 400, it is a leap year
print("%d is a leap year"%year)
elif(year%100==0):
#if the year id divided by 100, it is not a leap year
#except divided by 400
print("%d is not a leap year"%year)
elif(year%4==0):
#if the year id divided by 4, it is a leap year
print("%d is a leap year"%year)
else:
print("%d is not a leap year"%year)
#If the all statements are false it is not a leap
When the above code is executed, it produces the following result
Case 1
Please enter the year for check leap or not: 2300 2300 is not a leap year
Case 2
Please enter the year for check leap or not: 2204 2204 is a leap year
Check if the given year is leap year using Nested if
Here, The program allows the user to enter the year and then it will check the given year is a leap year or not, using Nested if elae statements in Python language
Program 3
#Python program to check leap year using Nested if statements
year=int(input("Please enter the year for check leap or not: "))
#Ask input from the user and store the value in the year variable
if(year%4==0):
if(year%100==0):
if(year%400==0):
#if the all statements are true
# it is a leap year
print("%d is a leap year"%year)
#if the all statements are false
# it is not a leap year
else:
print("%d is not a leap year"%year)
else:
print("%d is a leap year"%year)
#it is a leap year
else:
print("%d is not a leap year"%year)
When the above code is executed, it produces the following result
Case 1
Please enter the year for check leap or not: 2044 2044 is a leap year
Case 2
Please enter the year for check leap or not: 2050 2050 is not a leap year
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