Program for count vowels and consonants of a string in C using ASCII value

In this article, we will discuss the concept of Program to count vowels and consonants of a string in C using ASCII value

In this post, we are going to learn how to count the vowels and consonants in the given string using ASCII value in C programming language

Program for count vowels and consonants of a string in C using ASCII value — count vowels and consonant

Code to count the vowels and consonants using for loop

The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using for loop in C language

Program 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];
    int i;
    int vowelCount=0,consonantCount=0;

    printf("Please enter a string\n");
    gets(str);
    for(i=0; str[i]!='\0'; i++){

    if(str[i] == 97|| str[i] == 101|| str[i] == 105|| str[i] == 111|| str[i] == 117
    ||str[i] == 65|| str[i] == 69|| str[i] == 73|| str[i] == 79|| str[i] == 85 ){
        vowelCount++;
    }
    else if((str[i] >= 97 && str[i] <= 122 || str[i] >= 65 && str[i] <= 90 )){
        consonantCount++;
    }
}
printf("The number of vowels: %d",vowelCount);
printf("\nThe number of consonants: %d",consonantCount);

getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter a string
C program
The number of vowels:2
The number of consonants: 6

Approach

Declare a string using character Array as char str[100];
Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
The user asked to enter a string to count vowels and consonants
A for-loop is used to count total vowels and consonants of the given string
It is initialized as i=0, and checks the test-expression and executes the loop until the given condition becomes true
Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
When the if-condition is false, control moves to else if and checks the test expression of else-if
If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
If the test expression of else-if is false, control skips from the loop
Finally, the program displays the number of vowels and consonants of the given string.

Code to count the vowels and consonants using while loop

The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using while loop in C language

Program 2

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];
    int i;
    int vowelCount=0,consonantCount=0;

    printf("Please enter a string\n");
    gets(str);
    i=0;
    while(str[i]!='\0'){

    if(str[i] == 97|| str[i] == 101|| str[i] == 105|| str[i] == 111|| str[i] == 117
    ||str[i] == 65|| str[i] == 69|| str[i] == 73|| str[i] == 79|| str[i] == 85 ){
        vowelCount++;
    }
    else if((str[i] >= 97 && str[i] <= 122 || str[i] >= 65 && str[i] <= 90 )){
        consonantCount++;
    }
     i++;
}
printf("The number of vowels: %d",vowelCount);
printf("\nThe number of consonant: %d",consonantCount);

getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter a string
code for coding
The number of vowels: 5
The number of consonants: 8

Approach

Declare a character Array as char str[100];
Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
The user asked to enter a string to count vowels and consonants
A while-loop is used to count total vowels and consonants of the given string
It is initialized as i=0, and checks the test expression and executes the loop until the given condition becomes true
Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
When the if-condition is false, control moves to else-if and checks the test expression of else-if
If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
If the test expression of else-if is false, control skips from the loop
Finally, the program displays the number of vowels and consonants of the given string.

Code to count the vowels and consonants using do-while loop

The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using do-while loop in C language

Program 3

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];
    int i;
    int vowelCount=0,consonantCount=0;

    printf("Please enter a string\n");
    gets(str);
    i=0;
   do{

    if(str[i] == 97|| str[i] == 101|| str[i] == 105|| str[i] == 111|| str[i] == 117
    ||str[i] == 65|| str[i] == 69|| str[i] == 73|| str[i] == 79|| str[i] == 85 ){
        vowelCount++;
    }
    else if((str[i] >= 97 && str[i] <= 122 || str[i] >= 65 && str[i] <= 90 )){
        consonantCount++;
    }
     i++;
} while(str[i]!='\0');
printf("The number of vowels: %d",vowelCount);
printf("\nThe number of consonant: %d",consonantCount);

getch();
    return 0;
}

Please enter a string

C programming language
The number of vowels: 7
The number of consonants: 13

Approach

Declare a character Array as char str[100];
Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
The user asked to enter a string to count vowels and consonants
A do-while loop is used to count total vowels and consonants of the given string
It is initialized as i=0, and checks the test-expression and executes the loop until the given condition becomes true
Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
When the if-statement is false, control moves to else-if and checks the test expression of else-if
If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
If the test expression of else-if is false, control skips from the loop
Finally, the program displays the number of vowels and consonants of the given string.