Java program to find the sum of natural numbers using recursion
Java program to find the sum of natural numbers using recursion
In this tutorial, we will discuss a concept of Java program to find the sum of natural numbers using recursion
In this article, we are going to learn how to find the sum of natural numbers using recursion in the Java programming language
What are Natural numbers
The positive integer numbers 1,2,3,4….n are known as natural numbers
Program
This program allows to enter a number to find addition of natural numbers from 1 to given number using recursive function in Java programming language
import java.util.Scanner;
class SumOfNum1{
public static void main(String args[]){
int sum; //variable declaration
Scanner scan=new Scanner(System.in);
//create a scanner object for input
System.out.print("Enter the value for num: ");
int num=scan.nextInt();
sum=addNumbers(num);
System.out.print("Sum of natural numbers are:"+sum);
}
static int addNumbers(int num)
{
if(num!= 0)
return num+addNumbers(num-1);
else
return num;
}
}
When the above code is executed, it produces the following results
Enter a value for num: 50 Sum of natural numbers are: 1275
In the above program , the number entered by the user is passed to the addNumber() function as an argument.
In the above case, when the user enters 50 as an argument, 50 is passed to function. Subsequently, until “if” statement returns the true value, value decreases by one in every step. Finally, when the value becomes 0, “if” statement returns as false and the “else” part is executed.
Therefore, function return with decreasing value to calculate the result e.g 1+2+3+4+5…..48+49+50=1275
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