Cpp program to check whether a number is even or odd

In this tutorial, we will discuss the Cpp program to check whether a number is even or odd

In this program, we are going to learn about how to find odd or even number from given number using if else statements in C++ programming language

What is Even or Odd

When the number is divided by 2 and the balance becomes zero. the above number is called as the even number – eg 2,4,6,8,10

and on the other sides when it is divided by 2 and balance becomes 1 there are called odd numbers or uneven numbers

Once This program received the number it will check the given number either odd or even.

After the program received input from the user, it is stored in the variable of num. then program divides the value of num into 2 and displays the output

Using modular operator

Program 1

#include <iostream>
#include <conio.h>

using namespace std;

int main()
{
    int num;
    cout << "Enter a integer number: " << endl;
    cin>>num;
    if(num%2==0)
        cout<<num<<"is an even";
    else
        cout<<num<<"is an odd";
    getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter an integer value: 44
44 is an even

case 2

Enter an integer value: 65
65 is an odd

when we use the modular operator, if it is the remainder appears as 0, it is called even number and if the remainder displays the balance as one, it is called as odd or uneven number

Using ternary operator

Program 2

#include <iostream>
#include <conio.h>

using namespace std;

int main()
{
    int num;
    cout << "Enter an integer number: " << endl;
    cin>>num;
    (num%2==0)? cout <<num<<" is an even number":cout<<num<<" is an odd number";
    getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter an integer value: 78
78 is an even number

case 2

Enter an integer value: 99
99 is an odd number

Using Bitwise operator

Program 3

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
    cout << "Enter the integer number" << endl;
    cin>>num;

    if(num & 1)
        cout<<num<<"is an odd number";
    else
        cout<<num<<"is an even number";
        getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter an integer value: 43
43 is an odd number

case 2

Enter an integer value: 68
68 is an even number

Using divisional operators

Program 4

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
    cout << "Enter the integer number" << endl;
    cin>>num;

    if((num /2)*2==num)
        cout<<num<<"is an even number";
    else
        cout<<num<<"is an odd number";
        getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter an integer value: 88
88 is an even number

case 2

Enter an integer value: 47
47 is an odd number

Program 5

Using shift operators

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
    cout << "Enter the number" << endl;
    cin>>num;

    if(((num>>1)<<1)==num ){
        cout<<num<<"is even ";
    }

    else{
        cout<<num<<"is odd";
    }
    getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1