Check whether an Alphabet is vowel or consonant in C language

Check whether an Alphabet is a vowel or consonant in C language

In this article, we will discuss the concept of Program to Check whether an Alphabet is a vowel or consonant in C programming  language

In this post, we are going to learn how to find whether and the given alphabet is vowel or consonant in c language

Check an Alphabet is a vowel or consonant using if-else

Program 1

The program allows the user to enter an Alphabet thereafter it will  check and display the result of the given Alphabet whether it is a vowel or consonant using the if-else statements in C programming language

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char ch;

    printf("Enter an Alphabet\n");
    scanf("%c",&ch);//Takes character input from the user

          //Checking both of lower case and upper case using || (or) operator
          if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{
    printf("%c is vowel",ch);//Display vowels
}
else{
    printf("%c  is  consonant",ch);//display consonant

}
getch();
    return 0;

}

When te above code is executed, it produces the following result

case 1

Enter an Alphabet
A
A is vowel

case 2

Enter an Alphabet
e
e is vowel

 

case 3

Enter an Alphabet
H
H is consonant

 

case 4

Enter an Alphabet
m
m is consonant

 

Approach

• In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
• The program evaluates whether the entered Alphabet is vowel or consonant using if-else statements
• If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not a vowel it will display”it is consonant”

 

 

 

Check an Alphabet is a vowel or consonant using if else-if else

Program 2

The program allows the user to enter an Alphabet thereafter it will  check and display the result of the given Alphabet whether it is a vowel or consonant using the if-else statements in C programming language

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char ch;
    printf("Enter a character\n");
    scanf("%c",&ch);//Takes character input from the user
    if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{//if statements checks vowels
    printf("%c is vowel",ch);//display vowel
}
else if//else if statement checks consonant
((ch>='A' && ch<='Z')||(ch>='a' && ch<='z')){
    printf("%c is  consonant",ch);//display consonamt
}
else{
printf("%c is not an alpabet",ch);//display non-alphabet
}
getch();
    return 0;
}

 

When te above code is executed, it produces the following result

case 1

Enter a character
A
A is vowel

 

case 2

Enter a character
i
i is vowel

 

case 3

Enter a character
G
G is consonant

 

case 4

Enter a character
j
j is consonant

 

case 5

Enter a character
&
& is not Alphabet

 

Approach

• In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
• The program evaluates whether the entered Alphabet is vowel or consonant using if-else -if-else statements
• If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not a vowel it will display”it is consonant”

 

Check an Alphabet is a vowel or consonant using Nested if-else

Program 3

The program allows the user to enter an Alphabet thereafter it will  check and display the result of the given Alphabet whether it is a vowel or consonant using the nested if-else statements in C programming language

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char ch;
    printf("Enter a character\n");
    scanf("%c",&ch);
    if((ch>='A' && ch<='Z')||(ch>='a' && ch<='z')){ //outer if use to check consonant

    if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{//inner if statements checks vowels
    printf("%c is vowel",ch);
}
else{//display consonant
printf("%c is consonant",ch);
}

}
else{
printf("%c is neither a vowel nor a consonant",ch);
}//display non-alphabet

getch();
    return 0;
}

When te above code is executed, it produces the following result

case 1

Enter a character
U
U is vowel

 

case 2

Enter a character
o
o is vowel

 

case 3

Enter a character
D
D is consonant

 

case 4

Enter a character
j
j is consonant

 

case 5

Enter a character
&
& is nither a vowel nor a consonant

Approach

• In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
• The program evaluates whether the entered Alphabet is vowel or consonant using Nested if statements
• If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not a vowel it will display”it is consonant”

 

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