In this tutorial, we will discuss a concept of the C++ code to calculate the average of odd and even numbers.
In this article, we are going to learn how to calculate the Average of odd and even numbers in the C++ programming language
When any integer ends in 0,2,4,6,8 and it can be divided by two with the remainder of zero, it is called as an even number.
Example of even numbers – 34,-64,78,788
When any integer ends in 0,1,3,5,7,9 and it cannot be divided without a remainder, it is called as an odd number.
Example for odd numbers – 33,-69,75,785
Here, We can use a modular operator to find odd or even number in the range of numbers
if n%2==0, n is an even number – if the number is even, the remainder is zero.
if n%2==1, n is an odd number – if the number is odd, the remainder is one.
Program 1
This program allows the user to enter a value and calculate average of odd and even numbers until the entered number using “for loop”.
Program
#include <iostream> #include <conio.h> using namespace std; int main() { int i,num, oddSum=0,evenSum=0,oddCount=0,evenCount=0; //1 double evenAvg,oddAvg; //2 cout<<"Enter the value for num: "; //3 cin>>num; for(i=1; i<=num; i++){ //4 if(i % 2==0){ //5 evenSum=evenSum+i; evenCount++; } else{ //6 oddSum=oddSum+i; oddCount++; } } evenAvg=evenSum/evenCount; //7 oddAvg=oddSum/oddCount; cout<<"Average of odd numbers are: "<<oddAvg; //8 cout<<"\n"; cout<<"Average of even numbers are: "<<evenAvg; getch(); return 0; }
When the above code is executed, it produces the following results
Enter the value for num: 60 Average of odd numbers are: 30 Average of even numbers are: 31
Method:
program
This program allows the user to enter a value and calculate average of odd and even numbers until the entered value using “while loop”.
#include <iostream> #include <conio.h> using namespace std; int main() { int i,num, oddSum=0,evenSum=0,oddCount=0,evenCount=0; //1 double evenAvg,oddAvg; //2 cout<<"Enter the value for num: "; //3 cin>>num; i=1; while(i<=num){ //4 if(i % 2==0){ //5 evenSum=evenSum+i; evenCount++; } else{ //6 oddSum=oddSum+i; oddCount++; } i++; } evenAvg=evenSum/evenCount; //7 oddAvg=oddSum/oddCount; cout<<"Average of odd numbers are: "<<oddAvg; //8 cout<<"\n"; cout<<"Average of even numbers are: "<<evenAvg; getch(); return 0; }
When the above code is executed, it produces the following results
Enter the value for num: 35 Average of odd numbers are: 18 Average of even numbers are: 18
Method:
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