C++ program to read and print elements of an one dim array
C++ program to read and print elements of an one dimensional array
In this tutorial, we will discuss the concept of C++ program to read and print elements a one dimensional array
In this topic, we are going to learn how to read and print elements of one dimensional array in C++ programming language
using loops
We have already discuss “What is an array“, “type of arrays” and “how to access it”
Arrays are the special type of variables to store Multiple type of values(int, string,char, etc)under the same name in the continuous memory location. we can be easily accessed through the indices(indexes)
Here,
- e1,e2,e3,e4 and e5 represent the elements of the array
- 0,1,2,3 and 4 represent the index of the array which is used to access the array elements
- 1,2,3,4 and 5 represent the length of an array
Code to read and print elements in an one dim array
Read and print elements Using for loop
In this program, we are briefing input elements in an array and then print them using for loop in C++ language
Program 1
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int i,len;
cout<<"Enter the Array length: ";
//Ask input for array length
cin>>len;
//Reading the input for array length
int num[len];
//Array declaration
cout<<"\n";//move to next line
cout<<"Enter the Number for array :";
//Ask input for elements(marks)
for(i=0; i<len; i++){//input using for loop
cin>>num[i];
//Reading the array elements from user
}
cout<<"\ndisplay the number\n";
for(i=0; i<len; i++){//display elements using for loop
cout<<num[i];
cout<<("\n");
}
getch();
return 0;
}
When the above code is executed, it produces the following result
Program 2
In this program, we are briefing input elements in an array and then print them using for loop in C++ language
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int i,len;
cout<<"Enter the Array length: ";
//Ask input for array length
cin>>len;
//Reading the input for array length
int num[len];
//Array declaration
cout<<"\n";//move to next line
//Ask input for elements(marks)
for(i=0; i<len; i++){//input using for loop
cout<<"Enter the number "<<"num["<<i<<"] :";
cin>>num[i];
//Reading the array elements from user
}
cout<<"\ndisplay the number\n";
for(i=0; i<len; i++){//display elements using for loop
cout<<"marks["<<i<<"] :"<<num[i];
cout<<("\n");
}
getch();
return 0;
}
When the above code is executed, it produces the following result
Read and print elements Using while loop
In this program, we are briefing input elements in an array and then print them using while loop in C++ language
Program 1
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int i,len;
cout<<"Enter the Array length: ";
//Ask input for array length
cin>>len;
//Reading the input for array length
int num[len];
//Array declaration
cout<<"\n";//move to next line
cout<<"Enter the Number for array :";
//Ask input for elements(marks)
i=0;
while(i<len){//input using while loop
cin>>num[i];
//Reading the array elements from user
i++;
}
cout<<"\ndisplay the number\n";
i=0;
while(i<len){//display elements using while loop
cout<<num[i];
cout<<("\n");
i++;
}
getch();
return 0;
}
When the above code is executed, it produces the following result
Program 2
In this program, we are briefing input elements in an array and then print them using while loop in C++ language
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int i,len;
cout<<"Enter the Array length: ";
//Ask input for array length
cin>>len;
//Reading the input for array length
int num[len];
//Array declaration
cout<<"\n";//move to next line
i=0;
//Ask input for elements(number)
while( i<len){//input using while loop
cout<<"Enter the number "<<"num["<<i<<"] :";
cin>>num[i];
//Reading the array elements from user
i++;
}
cout<<"\ndisplay the number\n";
i=0;
while(i<len){//display elements using while loop
cout<<"marks["<<i<<"] :"<<num[i];
cout<<("\n");
i++;
}
getch();
return 0;
}
When the above code is executed, it produces the following result
Read and print elements Using do-while loop
In this program, we are briefing input elements in an array and then print them using do-while loop in C++ language
Program 1
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int i,len;
cout<<"Enter the Array length: ";
//Ask input for array length
cin>>len;
//Reading the input for array length
int num[len];
//Array declaration
cout<<"\n";//move to next line
cout<<"Enter the Number for array :";
//Ask input for elements(marks)
i=0;
do{//input using do-while loop
cin>>num[i];
//Reading the array elements from user
i++;
}while(i<len);
cout<<"\ndisplay the number\n";
i=0;
do{//display elements using do-while loop
cout<<num[i];
cout<<("\n");
i++;
}while(i<len);
getch();
return 0;
}
When the above code is executed, it produces the following result
Program 2
In this program, we are briefing input elements in an array and then print them using do-while loop in C++ language
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int i,len;
cout<<"Enter the Array length: ";
//Ask input for array length
cin>>len;
//Reading the input for array length
int num[len];
//Array declaration
cout<<"\n";//move to next line
i=0;
//Ask input for elements(number)
do{//input using do-while loop
cout<<"Enter the number "<<"num["<<i<<"] :";
cin>>num[i];
//Reading the array elements from user
i++;
}while( i<len);
cout<<"\ndisplay the number\n";
i=0;
do{//display elements using do-while loop
cout<<"marks["<<i<<"] :"<<num[i];
cout<<("\n");
i++;
}while(i<len);
getch();
return 0;
}
When the above code is executed, it produces the following result
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