• On September 14, 2019
• By Karmehavannan
• 0 Comment
• Categories: Calculations, multiply
• Tags: C++ programs, Cpp language

C++ program to multiply two numbers without using arithmetic operator

C++ program to multiply two numbers without using arithmetic operator

problem – C++  program to multiply two numbers without using arithmetic operator

In this tutorial, we will discuss the concept of  multiplying two numbers without using arithmetic operator in C++ language. 

In this post, we will learn how to get the product of two number without arithmetic operator in C++ programming language

C++ program to find product of two numbers

Using for loop – Program 1

This program is used to find the multiplication of two numbers entered by the user – using for loop without arithmetic operator

#include <iostream>
#include <conio.h>
using namespace std;
int add(int n1, int n2);  //function prototype
int main()
{
    int n1,n2,product=0,i;
     cout << "Enter the first number: " ;
    cin>>n1;
    cout<<"Enter first  number: ";
    cin>>n2;
    for(i=0; i<n2; i++){
    product=add(product,n1); //function call
}
cout<<"product of "<<n1<<" and "<<n2<<" is: "<<product;
    getch();
    return 0;
}

int add(int num1,int num2){  //function definition
    int i;
for(i=0; i<num2; i++)
   num1++;
return num1;
    return 0;
}

When the above code is executed, it produces the following result

Enter the first number: 32
Enter the second number: 5
Product of 32 and 5 is: 160

Using while loop – Program 2

This program is used to find the multiplication of two numbers entered by the user – using while loop without arithmetic operator

#include <iostream>
#include <conio.h>
using namespace std;
int add(int n1, int n2);//function prototype
int main()
{
    int n1,n2,product=0,i;  //variable declaration
     cout << "Enter the first number: " ;
    cin>>n1;   //takes input from user for n1
    cout<<"Enter the second number: ";
    cin>>n2;  //takes input from user for n2
    for(i=0; i<n2; i++){
    product=add(product,n1);//function call
}
cout<<"product of "<<n1<<" and "<<n2<<" is: "<<product;
    getch();
    return 0;
}

int add(int num1,int num2){  //function definition
    while(num2 != 0){
int num3=(num1 & num2);
num1=num1^num2;
num2=num3<<1;

}
return num1;
}

When the above code is executed, it produces the following results

Enter the first number: 22
Enter the second number: 5
Product of 32 and 5 is: 110

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