C++ program to display all odd or even numbers 1 to n with label

Karmehavannan

6 years ago

C++ program to display all odd or even numbers from 1 to n with label

In this article, we will discuss the concept of C++ program to display all odd or even numbers from 1 to n with label using loops

In this post, we will learn how to find and display odd and even numbers from 1 to n with label using the loops.

Here, we will use for loop, while loop and do-while loop to find and display odd and even numbers from 1 to n in C++ programming language.

C++ program to display all odd or even numbers

Using for loop

This program allows the user to enter the maximum numbers. It finds and displays even and odd numbers with label 1 to entered number using for loop.

program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num,i;  //variable declaration
    cout<<"Enter the random number \n";
    cin>>num;//takes input from user(maximum number)

    cout<<"Display all odd and even number till "<<num;

cout<<"\n\n";

for(i=1; i<=num; i++){
    if(i%2==0){
        cout<<i;
                cout<<" Is Even";
        cout<<"\t";
    }

    else{
        cout<<i;
                cout<<" Is Odd\t";
    }

}
getch();
    return 0;
}

When the above code is executed, it produces the following results

Display the number – odd or even with label using loops

C++ program to find the number is odd or even with label using loops — Display the number – odd or even with label using loops

Using while loop

Program 2

This program allows the user to enter the maximum numbers. It finds and displays even and odd numbers with label 1 to entered number using while loop.

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num,i;//variable declaration
    cout<<"Enter the random number \n";
    cin>>num;//Takes input from user(maximum number)

    cout<<"Display all odd and even number till "<<num;

cout<<"\n\n";

i=1;
while(i<=num){
    if(i%2==0){
        cout<<i;
                cout<<" Is Even";
        cout<<"\t";
    }

    else{
        cout<<i;
                cout<<" Is Odd\t";
    }
     i++;

}
getch();
    return 0;
}

When the above code is executed, it produces the following results

Using do-while loop

Program 3

This program allows the user to enter the maximum numbers. It finds and displays even and odd numbers with label 1 to entered number using the do-while loop.

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num,i;//variable declaration
    cout<<"Enter the random number \n";
    cin>>num;//Takes input from user

    cout<<"Display all odd and even number till "<<num;

cout<<"\n\n";

i=1;
do{
    if(i%2==0){
        cout<<i;
                cout<<" Is Even";
        cout<<"\t";
    }

    else{
        cout<<i;
                cout<<" Is Odd\t";
    }
     i++;

}while(i<=num);
getch();
    return 0;
}

When the above code is executed, it produces the following results