C++ program to check odd or even using recursion
In this tutorial, we will discuss a concept of the C++ program to check odd or even in given number using recursion
In this article, we are going to learn how to check of odd and even numbers using recursion in the C++ programming language
What is an even or odd number?
When any integer ends in 0,2,4,6,8 and it can be divided by two with the remainder of zero, it is called as an even number.
Example of even numbers – 34,-64,78,788
When any integer ends in 0,1,3,5,7,9 and it cannot be divided without a remainder, it is called as an odd number.
Example for odd numbers – 33,-69,75,785
Here, We can use C++ programming operators to find odd or even number in a given number
C++ program to check odd or even using recursion
Program 1
This program allows the user to enter a number and is used to check whether the given number is odd or even using recursion
#include <iostream>
#include <conio.h>
using namespace std;
int isEven(int);//Function prototype/ declaration
int main()
{
int num;
//declare a variable num
cout << "Enter a number to find odd or even" << endl;
cin>>num;
//Take input from the user and stored in variable num
if(isEven(num)){
cout<<"It is a even number";
}
else{
cout<<"It is a odd number";
}
cout<<endl;
getch();
return 0;
}
int isEven(int num)//recursive function in C++
{ //function definition or function body
if(num==0){
return 1;
}
else if(num==1){
return 0;
}
else if(num<0){
return isEven(-num);
}
else
return isEven(num-2);
}
When the above code is executed, it produces the following results
case 1
Enter ta number to find odd or even 345 it is a odd number
case 2
Enter ta number to find odd or even 456 it is a even number
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