C++ program to count vowels and consonants in a string
C++ program to count vowels and consonants in a string
In this article, we will discuss the concept of C++ program to count vowels and consonants in a string
In this post, we are going to learn how to count the vowels and consonants in the given string in C++ programming language
code to count the vowels and consonants using for loop
The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using for loop in C++ language
Program 1
#include <iostream> #include <stdio.h> #include <conio.h> using namespace std; int main() { char str[100]; int i,vowCount=0,consCount=0; cout<<"Enter a string for count vowel and consonant\n"; gets(str);//store the input from user for(i=0; str[i]; i++){ if(str[i] == 'a'|| str[i] == 'e'|| str[i] == 'i'|| str[i] == 'o'|| str[i] == 'u' ||str[i] == 'A'|| str[i] == 'E'|| str[i] == 'I'|| str[i] == 'O'|| str[i] == 'U' ){ vowCount++;//vowel counter incremented by 1 } else if((str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z' )){ consCount++;//consonant counter incremented by 1 } } cout<<"Number of vowels:"<<vowCount<<endl;//display number of vowels cout<<"Number of consonants:"<<consCount<<endl;//display number of consonant getch(); return 0; }
When the above code is executed, it produces the following result
Enter a string for count vowel and consonant code for coding The number of vowels: 6 The number of consonants: 8
Approach
- Declare a character Array as char str[100];
- Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
- The user asked to enter a string to count vowels and consonants
- A for-loop is used to count total vowels and consonants of the given string
- It is initialized as i=0, and checks the test-expression and executes the loop until the given condition becomes true
- Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
- When the if-condition is false, control moves to else-if and checks the test expression of else-if
- If the test-expression of else if is true, consCount becomes consCount + 1(consCount =consCount +1)
- If the test expression of else if is false, control skips from the loop
- Finally, the program displays the number of vowels and consonants of the given string.
Code to count vowel and consonant using while loop
The program allows the user to enter a string thereafter It counts the vowels and consonants of the given string using while loop in C++ language
Program 2
#include <iostream> #include <stdio.h> #include <conio.h> using namespace std; int main() { char str[100]; int i,vowCount=0,consCount=0; cout<<"Enter a string for count vowel and consonant\n"; gets(str); i=0; while(str[i]){ if(str[i] == 'a'|| str[i] == 'e'|| str[i] == 'i'|| str[i] == 'o'|| str[i] == 'u' ||str[i] == 'A'|| str[i] == 'E'|| str[i] == 'I'|| str[i] == 'O'|| str[i] == 'U' ){ vowCount++; } else if((str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z' )){ consCount++; } i++; } cout<<"The number of vowels:"<<vowCount<<endl; cout<<"The number of consonant:"<<consCount<<endl; getch(); return 0; }
When the above code is executed, it produces the following result
Enter a string for count vowel and consonant CPP programming The number of vowels: 3 The number of consonants: 11
Approach
- Declare a character Array as char str[100];
- Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
- The user asked to enter a string to count vowels and consonants
- A while-loop is used to count total vowels and consonants of the given string using the vowCount and consCount variables
- It is initialized as i=0, and checks the test-expression and executes the loop until the given condition becomes true
- Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
- When the if-condition is false, control moves to else if and checks the test expression of else-if
- If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
- If the test expression of else if is false, control skips from the loop
- Finally, the program displays the number of vowels and consonants of the given string.
C++ program to count vowel and consonant using do-while loop
Program 3
#include <iostream> #include <stdio.h> #include <conio.h> using namespace std; int main() { char str[100]; int i,vowCount=0,consCount=0; cout<<"Enter a string for count vowel and consonant\n"; gets(str); i=0; do{ if(str[i] == 'a'|| str[i] == 'e'|| str[i] == 'i'|| str[i] == 'o'|| str[i] == 'u' ||str[i] == 'A'|| str[i] == 'E'|| str[i] == 'I'|| str[i] == 'O'|| str[i] == 'U' ){ vowCount++; } else if((str[i] >= 'a' && str[i] <= 'z' || str[i] >= 'A' && str[i] <= 'Z' )){ consCount++; } i++; } while(str[i]); cout<<"The number of vowels:"<<vowCount<<endl; cout<<"The number of consonants:"<<consCount<<endl; getch(); return 0; }
When the above code is executed, it produces the following result
Enter a string for count vowel and consonant CPP language The number of vowels: 4 The number of consonants: 7
Approach
- Declare a character Array as char str[100];
- Declare and initialize two integer counter variable as int vowCount=0 and consCount=0;
- The user asked to enter a string to count vowels and consonants
- A do-while-loop is used to count total vowels and consonants of the given string using the vowCount and consCount variables
- It is initialized as i=0, and checks the test-expression and executes the loop until the given condition becomes true
- Use an if statement to test vowel, if the test expression is true, vowCount becomes vowCount + 1(vowCount=vowCount+1)
- When the if-condition is false, control moves to else if and checks the test expression of else-if
- If the test-expression of else-if is true, consCount becomes consCount + 1(consCount =consCount +1)
- If the test expression of else if is false, control skips from the loop
- Finally, the program displays the number of vowels and consonants of the given string.
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