C++ code to sum of two integer using Bitwise operator

In this article, we will discuss the concept of the C++ code to sum of two integer using Bitwise operator

In this post, we are going to learn how to write a program to find the sum of two numbers using Bitwise operator in C++ programming language

Code to find the addition of two numbers

Addition of two integer using Bitwise operator

The program allows the user to enter two integers and then calculates sum of given numbers using Bitwise operator in C++ language

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int a,b,num1,num2;

    cout<<"Enter the first number: \n";
    cin>>num1;
//Ask the number from the user for num1
    cout<<"Enter the second number: \n";
    cin>>num2;
//Ask the number from the user for num2
    a=num1;//Assign the value of num1 to a
    b=num2;//Assign the value of num2 to b

    while (num2!= 0)
    {//Calculate the sum of two numbers using bitwise operator
        int count=num1 & num2;
        num1=num1^num2;
        num2=count<<1;
    }
    cout<<"Sum of two numbers "<<a<<" and "<<b<<" is: "<<num1;
//Display output on the screen
getch();
    return 0;
}

When the above code is executed, it produces the following result

Enter the first number: 200
Enter the second number: 300
Sum of two numbers 200 and 300 is: 500

Sum oft two integer using Bitwise operator

The program allows the user to enter two integers and then calculates sum of given numbers using Bitwise operator in C++ language

Program 2

#include <conio.h>
using namespace std;
int sub(int,int);
int main()
{
    int num1,num2,ans;
    cout<<"Enter two numbers: \n";
    cin>>num1>>num2;
//Ask input two integers and store the variables num1,num2
    ans=sub(num1,num2);//Calling the function
//and assign the output to variable ans
    cout<<"Sum of "<<num1<<" and "<<num2<<" is "<<ans;
    getch();
    return 0;
}
int sub(int x, int y){//function definition
  while(y!=0){//Calculate the sum of two numbers using bitwise operator
    int carry=x & y;
    x=x^y;
    y=carry<<1;
  }
  return x;
}

When the above code is executed, it produces the following result

Enter two numbers
125
375
Sum of 125 and 375 is: 500

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