C++ code to print Rhombus and Hollow Rhombus star pattern using for loop

Karmehavannan

4 years ago

C++ code to print Rhombus and Hollow Rhombus star pattern using for loop

In this article, we will discuss the concept of C++ code to print Rhombus and Hollow Rhombus star pattern using for loop

In this post, we are going to learn how to write a program to print rhombus and Hollow rhombus star pattern in C++ language using for loop.

Code to print Rhombus and Hollow Rhombus star pattern

Rhombus star pattern using for loop

This program allows the user to enter the number of rows and symbols then it will display the rhombus star pattern using for loop in C++ programming language

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main() {
    int i,j,rows;
    char ch;
    cout<<"Enter the number of rows\n";
cin>>rows;
cout<<"Enter the Symbol for pattern\n";
cin>>ch;
 cout<<"\n";
 for(i=1; i<=rows; i++){//outer for loop
   for(j=1; j<=rows-i; j++){//inner for loop
   cout<<" ";//print space
   }
   for(j=1; j<=rows; j++){//inner for loop
   cout<<ch;//print character after space
}
 cout<<"\n";//move to next line
}
getch();
    return 0;
}

When the above code is executed, it produces the following result

Hollow Rhombus star pattern using for loop

This program allows the user to enter the number of rows and symbols then it will display the Hollow Rhombus star pattern using for loop in C++ programming language

Program 2

#include <iostream>
#include <conio.h>
using namespace std;

int main() {
    int i,j,rows;
    char ch;
    cout<<"Enter the number of rows\n";
cin>>rows;
cout<<"Enter the Symbol for pattern\n";
cin>>ch;
 cout<<"\n";
 for(i=1; i<=rows; i++){//outer for loop
   for(j=1; j<=rows-i; j++){//inner for loop
   cout<<" ";//print space
   }
   for(j=1; j<=rows; j++){//inner for loop
        if(i==1 || i==rows || j==1 || j==rows )
   cout<<ch;//print character after space
    else
   cout<<" ";
    }
 cout<<"\n";//move to next line
}
getch();
    return 0;
}

When the above code is executed, it produces the following result