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In this tutorial, we will discuss a concept of the C code to display Diamond number pattern
In this post, we will learn how to create the diamond number pattern using loops in C language.
We can use for loop, while loop or do while loop to display different diamond number patterns in C programming language.
Here, we will use for loop to print different diamond number patterns
Program 1
#include <stdio.h> #include <stdlib.h> int main() { int rows; printf("Enter the number of rows: "); scanf("%d",&rows); int row=1,i,j,k; for(i=rows/2; i>0; i--){ //print upper part for(j=1; j<=i; j++){ printf(" ");//print space } for(j=1; j<=row; j++){ printf("%d",row); printf(" "); } printf("\n");//move to next line row++; } for(i=0; i<=rows/2; i++){ for(j=1; j<=i; j++){ printf(" ");//print space } for(j=row; j>=1; j--){ //print lower part printf("%d",row); printf(" "); } printf("\n");//move to next line row--; } return 0; }
When the above code is executed, it produces the following result
Enter the number of rows: 8 1 2 2 3 3 3 4 4 4 4 5 5 5 5 5 4 4 4 4 3 3 3 2 2 1
Program 2
#include <stdio.h> #include <stdlib.h> int main() { int i,j,k,l,rows; printf("|Enter the number of rows"); scanf("%d",&rows); for(i=1; i<=rows; i++){ //print upper part for(j=1; j<=rows-i; j++){ printf(" ");//print initial space for upper part } for(k=i; k>=1; k--){ printf("%d",k); } for(l=2; l<=i; l++){ printf("%d",l); } printf("\n");//move to next line } for(i=rows-1; i>=1; i--){ //print lower part for(j=0; j<=rows-1-i; j++){ printf(" ");//print initial space for lower part } for(k=i; k>=1; k--){ printf("%d",k); } for(l=2; l<=i; l++){ printf("%d",l); } printf("\n");//move to next line } return 0; }
When the above code is executed, it produces the following result
Enter the number of rows: 6 1 212 32123 4321234 543212345 65432123456 543212345 4321234 32123 212 1
Program 3
#include <stdio.h> #include <stdlib.h> int main() { int rows; printf("Enter the number of rows: "); scanf("%d",&rows); int row=1,i,j,k; for(i=1; i<=rows; i++){ //print upper part for(j=1; j<=rows-i; j++){ printf(" "); } for(k=1; k<=i; k++){ printf("%d",k); printf(" "); } printf("\n");//move to next line } for(i=1; i<=rows-1; i++){ //print lower part for(j=1; j<=i; j++){ printf(" "); } for(k=1; k<=rows-i; k++){ printf("%d",k); printf(" "); } printf("\n");//move to next line } }
When the above code is executed, it produces the following result
Enter the number of rows: 6 1 1 2 1 2 3 1 2 3 4 1 2 3 4 5 1 2 3 4 5 6 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1
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