C++ code to Count Uppercase, Lowercase,Special character and Numeric values

C++ code to Count Uppercase, Lowercase, Special character and Numeric values

In this article, we will discuss the concept of the C++ code to Count Uppercase, Lowercase, Special character and Numeric values in C++ language

In this post, we are going to learn how to count the total number of Uppercase, Lowercase, Special character and Numeric values of the given String in C++ programming language

Count Uppercase, Lowercase, Special character and Numeric values using for loop

The program allows the user to enter a String and then it counts and display the total number of upper case, lower case, numeric values and special characters of the given string using for loop in C++ programing language

Program 1

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;
int main()
{
    char str[100];
    int i;
    int upper=0,lower=0,num=0,special=0;;
    cout<<"Please enter the string \n";
    gets(str); 
    for(i=0; str[i] != '\0'; i++){
        //check for uppercase
            if(str[i]>='A' && str[i]<='Z') {
                upper++;
    }else if(str[i]>='a' && str[i]<='z') {//check lower case
                lower++;
    }else if(str[i]>='1' && str[i]<='9') {//check numeric value
                num++;
    }
    else{
        special++;
    }
    }
    cout<<"Upper case letters: "<<upper;
    cout<<"\nLower case letters: "<<lower;
    cout<<"\nnumbers: "<<num;
    cout<<"\nSpecial characters: "<<special;
    getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter the string
My_Code:code4coding.com
Upper case letters: 2
Lower case letters: 17
Numbers: 1
Special characters: 3

Approach

Declare a String variable as character array char str[100];
Declare and initialize an integer variables as int i, upper=0,lower=0,num=0,Special=0;
The user asked to enter a string to count upper case, lower case, Numeric, Special characters
The given string is stored in the variable str;
A for-loop is used to count total characters of the given string
It is initialized as i=0, checks the test-expression whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
Use an if condition to test if(str[i]>=’A’ && str[i]<=’Z’), if it is true, The upper becomes upper + 1(upper=upper+1);
When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The lower becomes lower + 1(lower=lower+1);
When it is false, control moves to the next else-if part and evaluates the test-expression of else-if. if it is true The num becomes num+1(num=num+1);
When it is false, control moves to the else part and executes the else part statements. the special becomes special+1
Finally, the program displays the total number of the upper case, lower case, Numeric, Special characters of the given string

C++ code to Count Uppercase, Lowercase, Special character and Numeric values using while loop

Program 1

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;
int main()
{
    char str[100];
    int i;
    int upper=0,lower=0,num=0,special=0;;
    cout<<"Please enter the string \n";
    gets(str);
    i=0;
  
    while(str[i] != '\0'){
        //check for uppercase
            if(str[i]>='A' && str[i]<='Z') {
                upper++;
                //check for lower case
    }else if(str[i]>='a' && str[i]<='z') {
                lower++;
                //check for numbers
    }else if(str[i]>='1' && str[i]<='9') {
                num++;
    }
    else{
        special++;
    }
    i++;
    }
    cout<<"Upper case letters: "<<upper;
    cout<<"\nLower case letters: "<<lower;
    cout<<"\nnumbers: "<<num;
    cout<<"\nSpecial characters: "<<special;
    getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter the string
code4coding.com:2020
Upper case letters: 0
Lower case letters: 13
Numbers: 4
Special characters: 4

Approach

Declare a String variable as character array char str[100];
Declare and initialize an integer variables as int i, upper=0,lower=0,num=0,Special=0;
The user asked to enter a string to count upper case, lower case, Numeric, Special characters
The given string is stored in the variable str;
A while-loop is used to count total characters of the given string using the count variable
It is initialized as i=0, checks the test-expression whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
Use an if condition to test if(str[i]>=’A’ && str[i]<=’Z’), if it is true, The upper becomes upper + 1(upper=upper+1);
When it is false, control moves to the else-if part and evaluates the test-expression of else-if. If it is true The lower becomes lower + 1(lower=lower+1);
When it is false, control moves to the next else-if part and evaluates the test-expression of else-if. If it is true The num becomes num+1(num=num+1);
When it is false, control moves to the else part and executes the else part statements. the special becomes special+1
Finally, the program displays the total number of the upper case, lower case, Numeric, Special characters of the given string

C++ code to Count Uppercase, Lowercase, Special character and Numeric values using do-while loop

Program 3

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;
int main()
{
    char str[100];
    int i;
    int upper=0,lower=0,num=0,special=0;;
    cout<<"Please enter the string \n";
    gets(str);
    i=0;
   
   do{
        //check for uppercase
            if(str[i]>='A' && str[i]<='Z') {
                upper++;
                //check for lower case
    }else if(str[i]>='a' && str[i]<='z') {
                lower++;
                //check for numbers
    }else if(str[i]>='1' && str[i]<='9') {
                num++;
    }
    else{
        special++;
    }
    i++;
    } while(str[i] != '\0');
    cout<<"Upper case letters: "<<upper;
    cout<<"\nLower case letters: "<<lower;
    cout<<"\nnumbers: "<<num;
    cout<<"\nSpecial characters: "<<special;
    getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter the string
code4coding.com:CodingSolution
Upper case letters: 2
Lower case letters: 25
Numbers: 1
Special characters: 2

Approach

Declare a String variable as character array char str[100];
Declare and initialize an integer variables as int i, upper=0,lower=0,num=0,Special=0;
The user asked to enter a string to count upper case, lower case, Numeric, Special characters
The given string is stored in the variable str;
A do-while-loop is used to count total characters of the given string.
It is initialized as i=0, checks the test-expression whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
Use an if condition to test if(str[i]>=’A’ && str[i]<=’Z’), if it is true, The upper becomes upper + 1(upper=upper+1);
When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The lower becomes lower + 1(lower=lower+1);
When it is false, control moves to the next else-if part and evaluates the test-expression of else-if. if it is true The num becomes num+1(num=num+1);
When it is false, control moves to the else part and executes the else part statements. the special becomes special+1
Finally, the program displays the total number of the upper case, lower case, Numeric, Special characters of the given string