• On September 14, 2024
• By Karmehavannan
• 0 Comment
• Categories: Floyd's triangle, Number pattern
• Tags: C++ patterns, Cpp language, Pattern

Reverse order number pattern in Cpp using for loop

In this tutorial, we will discuss a concept of Reverse order number pattern in Cpp using for loop

In C++ language, we can use for loop, while loop, do-while loop to display various number, star, alphabet and binary number patterns

In this topic, we demonstrate how to display  some reversed number  patterns using the nested for loop in Cpp language.

Pattern 1

Reverse order number pattern program 1

#include <iostream>
#include <conio.h>

using namespace std;

int main()
{
    int i,j,rows;//variable declaration
    cout<<"Enter the number of rows: ";
    cin>>rows;//Take input the number of rows from user
    cout<<"\n";
    for(i=1; i<=rows; i++){
        for(j=i; j>=1; j--){
          cout<<j;//Display pattern
    }
    cout<<"\n";//move to next line
    }
    getch();
    return 0;
}

 

When the above code is compiled and executed, it produces the following results

Enter the number of rows: 8

1
21
321
4321
54321
654321
7654321
87654321

 

Program 2

Reverse order number pattern program 2

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,j,rows;//variable declaration
    cout<<"Enter the number of rows: ";
    cin>>rows;//Take input the number of rows from user
    for( i=rows; i>=1; i--){
        for( j=rows; j>=i; j--){
        cout<<j<<" ";
    }
    cout<<"\n";//move to next line
    }
    getch();
    return 0;
}

When the above code is compiled and executed, it produces the following results

Enter the number of rows: 8
8
8 7 
8 7 6
8 7 6 5
8 7 6 5 4
8 7 6 5 4 3
8 7 6 5 4 3 2 
8 7 6 5 4 3 2 !

 

 

Pattern 3

Reverse order number pattern program 3

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,j,rows;//variable declaration
    cout<<"Enter the number of rows: ";
           cin>>rows;//Take input the number of rows from user
           for(i=rows; i>=1; i--){//outer loop
              for(j=i; j>=1; j--){//inner loop
               cout<<i<<" ";

           }
           cout<<"\n";//move to next line

           }
    return 0;
}

 

When the above code is compiled and executed, it produces the following results

Enter the number of rows: 7
7 7 7 7 7 7 7
6 6 6 6 6 6
5 5 5 5 5
4 4 4 4
3 3 3
2 2 
1

 

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