Program to Check whether an Alphabet is vowel or consonant in C++

Program to Check whether an Alphabet is a vowel or consonant in C++

In this article, we will discuss the concept of Program to Check whether an Alphabet is a vowel or consonant in C++ programming language

In this post, we are going to learn how to find whether the given alphabet is vowel or consonant in C++ language

Program to find whether an alphabet is a vowel or consonant

Program to find whether an alphabet is a vowel or consonant using if-else

Program 1

The program allows the user to enter an Alphabet thereafter it will  check and display the result of the given Alphabet whether it is a vowel or consonant using the if-else statements in C++ programming language

#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
    char ch;

    cout<<"Enter an Alphabet\n";
    cin>>ch;//Takes character input from the user

          //Checking both of lower case and upper case using || (or) operator
          if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{
    cout<<ch<<" is vowel";//Display vowels
}
else{
    cout<<ch<<" is  consonant";//display consonant

}
getch();
    return 0;

}

When the above code is executed, it produces the following result

case 1

Enter an Alphabet
A
A is vowel

 

case 2

Enter an Alphabet
i
i is vowel

 

case 3

Enter an Alphabet
S
S is consonant

 

case 4

Enter an Alphabet
h
h is consonant

 

Approach

• In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
• The program evaluates whether the entered Alphabet is a vowel or consonant, using if-else statements
• If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not vowel it will display”it is consonant”

 

program to find whether an Alphabet is a vowel or consonant using if-else if else

Program 2

The program allows the user to enter an Alphabet thereafter it will  check and display the result of the given Alphabet whether it is a vowel or consonant using the if else-if else statements in C++ programming language

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    char ch;
    cout<<"Enter a character\n";
    cin>>ch;//Takes character input from the user
    if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{//if statements checks vowels
    cout<<ch<<" is vowel";
}
else if//else if statement checks consonant
((ch>='A' && ch<='Z')||(ch>='a' && ch<='z')){
    cout<<ch<<"  is  consonant";
}
else{
cout<<ch<<" is not an alpabet";
}
getch();
    return 0;
}

 

When the above code is executed, it produces the following result

case 1

Enter an Alphabet
E
E is vowel

 

case 2

Enter an Alphabet
u
u is vowel

case 3

Enter an Alphabet
L
L is consonant

 

case 4

Enter an Alphabet
h
h is consonant

 

Case 5

Enter an Alphabet
@
@ is not an Alphabet

 

Approach

• In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
• The program evaluates whether the entered Alphabet is a vowel or consonant, using if-else-if else statements
• If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not vowel it will display”it is consonant”

 

program to find whether an Alphabet is a vowel or consonant using Nested if-else

Program 3

The program allows the user to enter an Alphabet thereafter it will  check and display the result of the given Alphabet whether it is a vowel or consonant using the Nested  if-else statements in C++ programming language

 

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    char ch;
    cout<<"Enter a character\n";
    cin>>ch;//Takes caracter input from the user
    if((ch>='A' && ch<='Z')||(ch>='a' && ch<='z')){ //outer if use to check consonant

    if(ch=='a'||ch=='A'||ch=='e'||ch=='E'||ch=='i'||ch=='I'||ch=='o'||ch=='O'||ch=='u'||ch=='U')
{//inner if statements checks vowels
    cout<<ch<<" is vowel";
}
else{//display consonant
cout<<ch<<" is consonant";
}

}
else{
cout<<ch<<" is neither a vowel nor a consonant";
}

getch();
    return 0;
}

When the above code is executed, it produces the following result

case 1

Enter an Alphabet
E
E is vowel

case 2

Enter an Alphabet
u
u is vowel

 

case 3

Enter an Alphabet
L
L is consonant

 

case 4

Enter an Alphabet
h
h is consonant

 

Case 5

Enter an Alphabet
@
@ is not an Alphabet

 

Approach

• In the program, the user is asked to enter an Alphabet and entered Alphabet is stored in character variable ch
• The program evaluates whether the entered Alphabet is a vowel or consonant, using Nested if-else statements
• If the given Alphabet is a vowel The program displays the output “it is a vowel” and if the given Alphabet is not vowel it will display”it is consonant”

 

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