Java program to find the sum of natural numbers using recursion

Java program to find the sum of natural numbers using recursion

In this tutorial, we will discuss a concept of  Java program to find the sum of natural numbers using recursion

In this article, we are going to learn  how to  find the sum of natural numbers using recursion in the Java programming language

What are Natural numbers

The positive integer numbers 1,2,3,4….n are known as natural numbers

Program

This program allows to enter a number to find addition of natural numbers from 1 to given number using recursive function in Java programming language

import java.util.Scanner;
class SumOfNum1{
public static void main(String args[]){
    int sum;  //variable declaration
    Scanner scan=new Scanner(System.in);
//create a scanner object for input

System.out.print("Enter the value for num: ");
int num=scan.nextInt();
     sum=addNumbers(num);
   System.out.print("Sum of natural numbers are:"+sum);
} 
static int addNumbers(int num)
{
    
    if(num!= 0)
        return num+addNumbers(num-1);
    else
        return num;
}
}

When the above code is executed, it produces the following results

Enter a value for num: 50
Sum of natural numbers are: 1275

In the above program , the number entered by the user is passed to the addNumber() function as an argument.

In the above case, when the user enters 50 as an argument, 50 is passed to function. Subsequently, until “if” statement returns the true value, value decreases by one in every step. Finally, when the value becomes 0, “if” statement returns as false and the “else” part is executed.

Therefore, function return with decreasing value to calculate the result e.g 1+2+3+4+5…..48+49+50=1275

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