Java program to check the given year is a leap year

Java program to check if the given year  is a leap year

In this article, we will discuss the concept of Java program to check if a given year  is a leap year

In this post, we are going to learn how to write a program to check  the given year is leap or not in  Java programming language.   using if block

 

What is leap year

A normal year contains 365 days but a leap year contains 366 days

leap year is occurring once every four years, which has 366 days including 29 February as an intercalary day. it is called leap year

Century year

The century year is ending with 00

Ex 2000, 2100, 2200

a century year may be a leap year but it is not compulsory

How to find the leap year

if The given year is perfectly divisible by 4 , it is a leap year(except century year)

only if is perfectly divisible by 400, the century year is a leap year,
a century year should be divisible by 4 and 100 both
a non century year should be divisible only by 4

 

program to check leap year using if else

Here, The program allows the user to enter the year and then it will check the year is a leap year or not, using if – else statements in Java language

Program 1

import java.util.Scanner;
public class Check_Leap_Year1{
public static void main(String args[]){
    
    Scanner sc=new Scanner(System.in);
    //Ask input from the user
    System.out.println("Please Enter year for check leap: ");
int year=sc.nextInt();
boolean is_Leap=false;
//Check leap year in one line
if ((year%400==0)||((year%4==0)&&(year%100!=0))){
    //if it is true display leap year
    //if it is false move to else part
       System.out.println(year+" is a leap year ");
}
       else{
       System.out.println(year+" is not a leap year ");
}
}
}

When the above code is executed, it produces the following result

Case 1

Please enter for check leap or not
2016
2016 is  a leap year

 

Case 2

Please enter for check leap or not
2022
2022 is  a not a leap year

 

program to check leap year using Nested if else

Here, The program allows the user to enter the year and then it will check the year is a leap year or not using Nested if – else statements in Java

Program 2

import java.util.Scanner;
public class Find_Leap_Year{
public static void main(String args[]){
    
    Scanner sc=new Scanner(System.in);
    
    System.out.println("Please Enter year for check leap or not: ");
int year=sc.nextInt();
boolean is_Leap=false;
//if the years is devided by 4
if(year%4==0){
    //if the years  is century
     if(year%100==0){
//if the years is devided by 400
//if all the above conditionsa is true, it is a leap year
           if(year%400==0){
      is_Leap=true;
        }else
    is_Leap=false;
//if the years  is not century
    } else
    is_Leap=true;
  }else
    is_Leap=false;
    
if(is_Leap==true)
       System.out.println(year+" is a leap year ");
   //display leap year
       else
       System.out.println(year+" is not a leap year ");
}
}

When the above code is executed, it produces the following result

Case 1

Please enter for check leap or not
1244
1244 is  a leap year

 

Case 2

Please enter for check leap or not
1366
1366 is  a not a leap year

 

Program to check leap year using if else if else

Here, The program allows the user to enter the year and then it will check the year is a leap year or ,using if – else-if else statements in Java language

Program 3

import java.util.Scanner;
public class find_Leap_Year2{
public static void main(String args[]){
    
    Scanner sc=new Scanner(System.in);
    
    System.out.println("Please Enter year for check leap or not: ");
int year=sc.nextInt();
boolean is_Leap=false;
//if years is divided by 400
if(year%400==0){
     System.out.println(year+" is a leap year ");
}
//if the year is century
else if(year%100==0){
    System.out.println(year+" is not a leap year ");
}
    //if the year is devided by 4
   else if(year%4==0){//then it is a leap year
        System.out.println(year+" is a leap year ");
   }
       else{
       System.out.println(year+" is not a leap year ");
}
}
}

When the above code is executed, it produces the following result

Case 1

Please enter for check leap or not
2020
2020 is  a leap year

 

Case 2

Please enter for check leap or not
2006
2006 is  a not a leap year

 

program to check leap year using ternary operator

Here, The program allows the user to enter the year and then it will check the year is a leap year or not using ternary operator in Java language

Program 4

import java.util.Scanner;
public class find_Leap_Year3{
public static void main(String args[]){
    
    Scanner sc=new Scanner(System.in);
    
    System.out.println("Please Enter year for check leap: ");
    //Ask input from the user
int year=sc.nextInt();
//store the in the year variable entered by user
String leap=(year%4==0 || year%100!=0 && year%400==0)? 
"The entered year is a leap year":"This is not a leap year"; 
System.out.println(leap);
}
}

When the above code is executed, it produces the following result

Case 1

Please enter for check leap or not
2020
The entered year is  a leap year

 

Case 2

Please enter for check leap or not
2022
This is not a leap year

 

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