amp-web-push-widget button.amp-subscribe { display: inline-flex; align-items: center; border-radius: 5px; border: 0; box-sizing: border-box; margin: 0; padding: 10px 15px; cursor: pointer; outline: none; font-size: 15px; font-weight: 500; background: #4A90E2; margin-top: 7px; color: white; box-shadow: 0 1px 1px 0 rgba(0, 0, 0, 0.5); -webkit-tap-highlight-color: rgba(0, 0, 0, 0); } /** * Jetpack related posts */ /** * The Gutenberg block */ .jp-related-posts-i2 { margin-top: 1.5rem; } .jp-related-posts-i2__list { --hgap: 1rem; display: flex; flex-wrap: wrap; column-gap: var(--hgap); row-gap: 2rem; margin: 0; padding: 0; list-style-type: none; } .jp-related-posts-i2__post { display: flex; flex-direction: column; /* Default: 2 items by row */ flex-basis: calc( ( 100% - var(--hgap) ) / 2 ); } /* Quantity qeuries: see https://alistapart.com/article/quantity-queries-for-css/ */ .jp-related-posts-i2__post:nth-last-child(n+3):first-child, .jp-related-posts-i2__post:nth-last-child(n+3):first-child ~ * { /* From 3 total items on, 3 items by row */ flex-basis: calc( ( 100% - var(--hgap) * 2 ) / 3 ); 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} #jp-relatedposts .jp-relatedposts-items-visual .jp-relatedposts-post-nothumbs span { margin-bottom: 1em; } /* List Layout */ #jp-relatedposts .jp-relatedposts-list .jp-relatedposts-post { clear: both; width: 100%; } #jp-relatedposts .jp-relatedposts-list .jp-relatedposts-post img.jp-relatedposts-post-img { float: left; overflow: hidden; max-width: 33%; margin-right: 3%; } #jp-relatedposts .jp-relatedposts-list h4.jp-relatedposts-post-title { display: inline-block; max-width: 63%; } /* * Responsive */ @media only screen and (max-width: 640px) { #jp-relatedposts .jp-relatedposts-items .jp-relatedposts-post { width: 50%; } #jp-relatedposts .jp-relatedposts-items .jp-relatedposts-post:nth-child(3n) { clear: left; } #jp-relatedposts .jp-relatedposts-items-visual { margin-right: 20px; } } @media only screen and (max-width: 320px) { #jp-relatedposts .jp-relatedposts-items .jp-relatedposts-post { width: 100%; clear: both; margin: 0 0 1em; } #jp-relatedposts .jp-relatedposts-list .jp-relatedposts-post img.jp-relatedposts-post-img, #jp-relatedposts .jp-relatedposts-list h4.jp-relatedposts-post-title { float: none; 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In this tutorial, we will discuss a concept of Java code to find the largest elements of an Array
In this topic, we learn how to find largest element of an array(Collection of elements)
This program gets “n” number of elements and Enter the elements of the array as input from the user. then, this program finds and displays the largest elements from the array using for loops.
In this programs, we can see step by step procedure for completion of the program.
import java.util.Scanner; class Array_Large{ public static void main (String args[]){ int max;//variable declaration System.out.println("Enter the number of elements in an array: "); Scanner scan=new Scanner(System.in); int n=scan.nextInt();//get input from user for array length int[] arr=new int[n];//declaring an array of n elements //for loop for get input from user for(int i=0; i<n; i++){ System.out.print("Enter the element "+(i+1)+" :");//n elements arr[i]=scan.nextInt();//get input from user for array } max=arr[0]; for(int i=0; i<n; i++){ if(max<arr[i]){ max=arr[i]; } } System.out.println("\nThe largest value is: "+max); }//display result on the screen }
When the above code is compiled and executed, it produces the following results
Enter the number of elements in an array: 5 Enter element 1: 67 Enter element 2: 98 Enter element 3: 64 Enter element 4: 90 Enter element 5: 23 The largest value is: 98
import java.util.Scanner; class Large_num{ public static void main (String args[]){ Scanner scan=new Scanner(System.in); System.out.print("Enter the number of elements in an array: "); double max; int n=scan.nextInt();//get input from user for array length double arr[]=new double[n]; //declaring an array of n elements //for loop takes input from user for(int i=0; i<n; i++){ System.out.print("Enter element "+(i+1)+": "); arr[i]=scan.nextDouble();//takes input from user for array } max=arr[0]; for(int i=0; i<n; i++){ if(max<arr[i]){ max=arr[i]; } } System.out.print("\nThe largest value is: "+max); }//display result on the result }
When the above code is compiled and executed, it produces the following results
Enter the number of elements in an array: 5 Enter element 1: 4.2 Enter element 2: 2.4 Enter element 1: 6.7 Enter element 2: 9.5 Enter element 2: 5.6 The largest elemets is: 9.5
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