Display even and odd numbers without if statement in C

Display even and odd numbers without if statement in C

In this tutorial, we will discuss the concept of Display even and odd numbers without if statement in C language

In this post, we are going to learn how to display even and odd numbers without if statement in C language.

 

First, we must understand how to identify odd and even numbers

What is Even or Odd

When the number is divided by 2 and the balance becomes zero and the above number is called as the even number – eg 2,4,6,8,10

and on the other sides when it is divided by 2 and balance becomes 1 they are called odd numbers or uneven numbers – eg – 1,3,5,7,9

 

In my previous post, I have explained the various approaches to print even and odd numbers using if statements  in C language

 

here, we will discuss how to print  odd and even numbers without if statements in C programming language

 

There are three programs given below

Print even and odd numbers using for loop

Program 1

The program allows the user to enter the maximum number for print odd and even numbers using for loop in C language

Then, it will display the even and odd numbers without using if statements in C language

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i,num;
    printf("Enter the maximum number\n");
    scanf("%d",&num);//reads input from user
    printf("Even numbers are :");

    //print even numbers using for loop without if statements
    for(i=2; i<=num; i+=2){
        printf("%d ",i);
    }

    printf("\nOdd numbers are :");
    //print odd numbers using for loop without if statements
    for(i=1; i<=num; i+=2){
        printf("%d ",i);
    }
    getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the maximum number
30
Even numbers are : 2  4  6  8  10  12  14  16  18  20  22  24  26  28  30
Odd numbers are : 1  3  5  7  9  11  13  15  17  19  21  23  25  27  29

 

Print even and odd numbers  using while loop

Program 2

The program allows the user to enter the maximum number for display odd and even numbers using while loop in C language

Then, it will display the even and odd numbers without using if statements in C language

 

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i,num;
    printf("Enter the maximum number\n");
    scanf("%d",&num);//reads maximum value from user
    printf("Even numbers are :");

    //print even numbers using for loop without if statements
    i=2;
    while(i<=num){
        printf("%d ",i);
         i+=2;
    }

    printf("\nOdd numbers are :");
    //print odd numbers using for loop without if statements
    i=1;
    while(i<=num){
        printf("%d ",i);
         i+=2;
    }
    getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the maximum number
20
Even numbers are :2  4  6  8  10  12  14  16  18  20
Odd numbers are : 1  3  5  7    11  13  15  17  19

 

Print even and odd numbers using the do-while loop

Program 3

The program allows the user to enter the maximum number for display odd and even numbers using do- while loop in C language

Then, it will display the even and odd numbers without using if statements in C language

 

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i,num;
    printf("Enter the maximum number\n");
    scanf("%d",&num);//reads maximum value from user
    printf("Even numbers are :");

    //print even numbers using for loop without if statements
    i=2;
    do{
        printf("%d ",i);
         i+=2;
    }while(i<=num);

    printf("\nOdd numbers are :");
    //print odd numbers using for loop without if statements
    i=1;
    do{
        printf("%d ",i);
         i+=2;
    }while(i<=num);
    getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the maximum number
30
Even numbers are : 2  4  6  8  10  12  14  16  18  20  22  24  26  28  30
Odd numbers are : 1  3  5  7  9  11  13  15  17  19  21  23  25  27  29

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