Display even and odd numbers without if statement in C++

In this tutorial, we will discuss a concept of the Display even and odd numbers without if statement in C++ programming language

In this post, we are going to learn how to display even and odd numbers without using if statement in C++ programming language.

First, we must understand how to identify an odd and even numbers

What is Even or Odd

When the number is divided by 2 and the balance becomes zero and the above number is called as the even number – eg 2,4,6,8,10

and on the other sides when it is divided by 2 and balance becomes 1 they are called as odd numbers or uneven numbers

-eg 1,3,5,7,9

In my previous post, I have explained the various approaches to print even and odd numbers using if statements in C++ language

here, we will discuss how to display odd and even numbers without if statements in C++ programming language

There are three programs given below

Print even and odd numbers using the for loop

Program 1

The program allows the user to enter a maximum number for display odd and even numbers using for loop in C++

It will display the even and odd numbers without using if statements

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Enter the maximum number\n";
    cin>>num;
    cout<<"Even numbers are :";

    //print even numbers using for loop without if statements
    for(i=2; i<=num; i+=2){
        cout<<i<<" ";
    }

    cout<<"\nOdd numbers are :";
    //print odd numbers using for loop without if statements
    for(i=1; i<=num; i+=2){
        cout<<i<<" ";
    }
    getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the maximum number
25
Even numbers are : 2  4  6  8  10  12  14  16  18  20  22  24
Odd numbers are : 1  3  5  7  9  11  13  15  17  19  21  23  25

print even and odd numbers using the while loop

Program 2

The program allows the user to enter the maximum number for print odd and even numbers using while loop in C++ language

It will print the even and odd numbers without using if statements

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Enter the maximum number\n";
    cin>>num;
    cout<<"Even numbers are :";

    //print even numbers using for loop without if statements
    i=2;
    while(i<=num){
        cout<<i<<" ";
         i+=2;
    }

    cout<<"\nOdd numbers are :";
    //print odd numbers using for loop without if statements
    i=1;
    while(i<=num){
        cout<<i<<" ";
         i+=2;
    }
    getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the Maximum number
30
Even numbers are : 2  4  6  8  10  12  14  16  18  20  22  24  26  28  30
Od numbers are: 1  3  5  7  9  11  13  15  17  19  21  23  25  27  29

Print even and odd numbers using the do-while loop

Program 3

The program allows the user to enter the maximum number for print odd and even numbers using the do-while loop in C++ language

Then, it will print the even and odd numbers without using if statements in C++ language

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int i,num;
    cout<<"Enter the maximum number\n";
    cin>>num;
    cout<<"Even numbers are :";

    //print even numbers using for loop without if statements
    i=2;
    do{
        cout<<i<<" ";
         i+=2;
    }while(i<=num);

    cout<<"\nOdd numbers are :";
    //print odd numbers using for loop without if statements
    i=1;
    do{
        cout<<i<<" ";
         i+=2;
    }while(i<=num);
    getch();
    return 0;
}

When the above code is executed, it produces the following results

Enter the maximum number
40
Even numbers are : 2  4  6  8  10  12  14  16  18  20  22  24  26  28  30  32  34  36  38  40
Odd numbers are: 1  3  5  7  9  11  13  15  17  19  21  23  25  27  29  31  33  35  37  39

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