C program to triangle number pattern

C program to triangle number pattern

In this tutorial, we will discuss how to write following C program to triangle number pattern

Here, some of Floyd’s triangle number patterns are written using nested for loop in C language

Program 1

Code to triangle number pattern 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int rows;
    printf("Triangle pattern 1\n\n");
    printf("Enter the rows: ");
    scanf("%d",&rows);
    int i,j;
    for(i=1; i<=rows; i++)
    {
        for(j=i; j<=rows; j++)
    {
        printf("%d",i);
    }
      printf("\n");
    }
   getch();
    return 0;
}

When the above code is executed, it produces the following results:

11111111
2222222
333333
44444
5555
666
77
8

 

Program 2

Code to triangle number pattern 2

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int rows;
    printf("Triangle pattern 1\n\n");
    printf("Enter the rows: ");
    scanf("%d",&rows);
    int i,j;
    for(i=1; i<=rows; i++)
    {
        for(j=i; j<=rows; j++)
    {
        printf("%d",j);
    }
      printf("\n");
    }
   getch();
    return 0;
}

When the above code is executed, it produces the following results:

12345678
2345678
345678
45678
5678
678
78
8

 

Program 3

Code to triangle number pattern 3

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int rows;
    printf("Triangle pattern 3\n\n");
    printf("Enter the rows: ");
    scanf("%d",&rows);
    int i,j,k;
    for(i=rows; i>=1; i--)
    {
        if(i%2==1){k=1;
        }
        else {k=i;}
        for(j=1; j<=i; j++)
    {
        printf("%d",k);
        if(i%2==1){k++;}
        else {k--;}

    }
      printf("\n");
    }
   getch();
    return 0;
}

When the above code is executed, it produces the following results:

87654321
1234567
654321
12345
4321
123
21
1

 

Program 4

Code to triangle number pattern 4

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int rows, i,j,k=1;
    printf("Enter the rows for pattern: ");
    scanf("%d",&rows);           //input from user
    printf("here your pattern\n");
    for(i=1; i<=rows; i++){   //for rows
        for(j=1; j<=i; j++){
        printf("%d",k);
        k++;
    }
    k--;
    for(j=1; j<=i-1; j++){
k--;
            printf("%d",k);
    }


        printf("\n");
        k=1;
    }
    getch();
    return 0;
}

When the above code is executed, it produces the following results:

Enter the rows for pattern:9
here your pattern
1
121
12321
1234321
123454321
12345654321
1234567654321
123456787654321
12345678987654321

 

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