In this tutorial, we will discuss a concept of the C++ program to print odd or even number between given range using recursion
In this article, we are going to learn how to print of odd and even numbers using recursion in the C++ programming language
When any integer ends in 0,2,4,6,8 and it can be divided by two with the remainder of zero, it is called as an even number.
Example of even numbers – 34,-64,78,788
When any integer ends in 0,1,3,5,7,9 and it cannot be divided without a remainder, it is called as an odd number.
Example for odd numbers – 33,-69,75,785
Here, We can use a C++ program operators to find odd or even number in a given range
Program 1
This program allows the user to enter two input(number) for the lower limit and upper limit. and it finds whether odd and even numbers in the given range(between upper limit to lower limit)
#include <iostream> #include <conio.h> using namespace std; //function declaration void displayEvenOdd(int num, int limit); int main() { int lowerLimit, upperLimit; cout<<"Enter your lower limit\n"; cin>>lowerLimit; //get input from user to lower limit cout<<"Enter your upper limit\n"; cin>>upperLimit; //get input from user to upper limit cout<<"Even/odd numbers from "<<lowerLimit<<" to "<<upperLimit<<endl; displayEvenOdd(lowerLimit, upperLimit); //function call with argument getch(); return 0; } void displayEvenOdd(int num, int limit)//recursive function { if(num>limit) return; cout<<num<<endl; displayEvenOdd(num + 2, limit); }
When the above code is executed, it produces the following results
case 1
Enter your lower limit 12 Enter your upper limit 24 Even/odd numbers from 12 to 24 12 14 16 18 20 22 24
case 2
Enter your lower limit 11 Enter your upper limit 25 Even/odd numbers from 11 to 25 11 13 15 17 19 21 23 25
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