C++ program to find the odd or even number using switch statements

C++ program to find odd or even number using switch statements

In this tutorial, we will discuss the concept of the C++ program to find an odd or even number using switch statements.

In this post, we are going to learn how to find odd or even number using switch statements in C++  programming language

 

when you divide a number by two and if the balance is zero, it is an even number

when you  divided a number by two  and if the balance is one, it is an odd number

Example of even number 2,4,6,8,…..

Example of odd number 1,3,5,7,…..

 

Here we will use a modular operator to display odd or even number of the given number

if n%2==0 n is an even number

if n%2==1 n is an odd number

 

C++ program to find odd or even number

Find the Even number – Standard method

The program will check and display the  even numbers from the given number using switch statements

Program 1

#include <iostream>
#include <conio.h>

using namespace std;

int main()
{
    int num1=452;
   // int num2=591;
switch(num1%2){ //this will return either 0 or 1
case 0:
    cout<<num1<<" is a even number";
    break;
case 1:
    cout<<num2<<" is a odd number";
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

452 is an even number

 

Find the Odd number – Standard method

The program will check and display the  odd numbers from the given number using switch statements

Program 2

#include <iostream>
#include <conio.h>

using namespace std;

int main()
{
    //int num1=452;
    int num2=591;
switch(num2%2){ //this will return either 0 or 1
case 0:
    cout<<num1<<" is a even number";
    break;
case 1:
    cout<<num2<<" is a odd number";
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

591 is an odd number

 

Find the odd or Even number – Entered by user

This program allows the user to enter a number and then, the program will check and display the  odd or even numbers from the given number(entered by the user) using switch statements

Program 3

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
    cout<<"Enter the number\n";
    cin>>num;

    switch(num%2){//this will return either 0 or 1
case 0:
   cout<<num<<" is a even number";
    break;
case 1:
    cout<<num<<" is a odd number";
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

Case 1

Enter the number
231
231 is an odd numbere

 

Case 2

Enter the number
1000
1000 is an even number

 

Approach

• The modular operator uses to find the modulus of the number dividing by 2.
• Switch statements return either 0 or 1.
• Then, check the case value with 0 or 1.
• if the case value is 0, the number will be even and case value 1, the number will be odd.

 

 

Suggested for you

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Switch statements in C++ language

 

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