In this article, we will discuss the concept of C program for check whether given year is leap using function
In this post, we are going to learn how to write a program to check the given year is leap or not, using function in C programming language
A normal year contains 365 days but a leap year contains 366 days
leap year is occurring once every four years, which has 366 days including 29 February as an intercalary day. it is called leap year
Century year
The century year is ending with 00
Ex 2000, 2100, 2200
a century year may be a leap year but it is not compulsory
How to find the leap year
if The given year is perfectly divisible by 4 , it is a leap year(except century year)
only if it is perfectly divisible by 400, the century year is a leap year,
a century year should be divisible by 4 and 100 both
a non century year should be divisible only by 4
Here, The program allows the user to enter the year and then it will check the year is a leap year or not, using function in C language
Program 1
#include <stdio.h>
#include <stdlib.h>
int leapYear(int);//function prototype
int main()
{
int year;//variable declaration
printf("Enter the year for check leap\n");
//Ask input from the user
scanf("%d",&year);
//store the value in the year variable
if(leapYear(year))//function definition
printf("%d is a leap year",year);
else
printf("%d is not a leap year",year);
getch();
return 0;
}
int leapYear(int y)//function definition
{
if((y%400==0)||((y%4==0)&&(y%100!=0)))
//Leap year if perfectly divisible by 400
//Leap year if perfectly divisible by 4
//but if not divisible by 100
return 1;
else//all other years are not leap year
return 0;
}
When the above code is executed, it produces the following result
Case 1
Enter the year for check leap 2028 2028 is a leap year
Case 2
Enter the year for check leap 2030 2030 is not a leap year
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