• On November 25, 2024
• By Karmehavannan
• 0 Comment
• Categories: Check value, function/method, If block
• Tags: C++ programs, Cpp language, User defined function

C++ program for check whether given year is leap using function

C++ program for check whether given year is leap using function

In this article, we will discuss the concept of C++ program for check whether given year is leap using function

In this post, we are going to learn how to write a program to check  the given year is leap or not using function  in  C++  programming language

check whether given year is leap using function

What is leap year

A normal year contains 365 days but a leap year contains 366 days

leap year is occurring once every four years, which has 366 days including 29 February as an intercalary day. it is called leap year

Century year

The century year is ending with 00

Ex 2000, 2100, 2200

a century year may be a leap year but it is not compulsory

How to find the leap year

if The given year is perfectly divisible by 4 , it is a leap year(except century year)

only if is perfectly divisible by 400, the century year is a leap year,
a century year should be divisible by 4 and 100 both
a non century year should be divisible only by 4

Code to check leap year using function

Here, The program allows the user to enter the year and then it will check the year is a leap year or not, using function in C++  language

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int leap_Year(int);//function prototype
int main()
{
    int year;//variable declaration
    cout<<"Enter the year for check leap year\n";
    //Ask input from the user
    cin>>year;
    //store the input value in the year variable
    if(leap_Year(year))//function call
        cout<<year<<" is a leap year";
    else
        cout<<year<<" is not a leap year";
        getch();
    return 0;
}

int leap_Year(int y)
{
    if((y%400==0)||((y%4==0)&&(y%100!=0)))
      //Leap year if perfectly divisible by 400
        //Leap year if perfectly divisible by 4
        //not a leap year if not divisible by 100
       return 1;
    else
        return 0;
}

When the above code is executed , it produces the following result

Case 1

Enter the year for check leap year
2032
2032 is a leap year

Case 2

Enter the year for check leap year
2038
2038 is not a leap year

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