C program: Count word,characters and space of a string

C program: Count word, characters and space of a string

In this article, we will discuss the concept of the C program: Count word, characters and space of a string

In this post, we are going to learn how to count the total number of words, character and Space of the given string in C programming language

C program: Count word, characters and space of a string

Count words, character and Space using for loop

The program allows the user to enter a String and then it counts and display the total number of words, character and Space of the given string using for loop in C programing language

Program 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];//declare and initialize char array
    int i;
    int words=1,characters=0,space=0;//display and initiolize variables
    printf("Please enter the string \n");
    gets(str);//stored the string entered by user

    for(i=0; str[i] != '\0'; i++){

            if(str[i]!=' '){ // check characters
                characters++;
            }
             else if(str[i]==' ' || str[i] != '\n' || str[i] != '\t'){ //check words
                words++;
            }
    }
printf("\nTotal words: %d ",words); //display words
printf("\nTotal characters: %d",characters);//display characters
printf("\nSpace: %d ",(words-1));//display space
getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter the string
This is C language

Total words: 4
Total characters: 15
Space: 3

Approach

1. Declare a Character array as char str[100];
2. Declare and initialize integer variables as words=1,space=0,caracters=0;
   
3. The user asked to enter a string
4. The given string is stored in the variable str;
5. A for loop is used to count total characters of the given string.
6. It is initialized as i=0, checks the condition whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
7. Use an if condition to test if(str[i]!=’ ‘), if it is true,  The characters becomes characters + 1( characters = characters +1);
8. When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The words becomes words+1(words=words+1);
9. Finally, the program displays the total number of the words, characters and Space of the given string

Count word, characters and space using while loop

The program allows the user to enter a String and then it counts and display the total number of words, character and Space of the given string using while loop in C programing language

Program 2

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];
    int i;
    int words=1,characters=0,space=0;
    printf("Please enter the string \n");
    gets(str); //store the given string

    i=0;
    while(str[i] != '\0'){

            if(str[i]!=' '){ // count characters
                characters++;
            }
             else if(str[i]==' ' || str[i] != '\n' || str[i] != '\t'){
                words++; // count words
            }
            i++;
    }
printf("\nTotal words: %d ",words);  //display total number of words
printf("\nTotal characters: %d",characters);  //display total number of characters
printf("\nSpace: %d ",(words-1));  //display total number of space
getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter the string
code4coding.com C language tutorials

Total words: 4
Total characters: 33
Space: 3

Approach

1. Declare a Character array as char str[100];
2. Declare and initialize integer variables as words=1,space=0,caracters=0;
   
3. The user asked to enter a string
4. The given string is stored in the variable str;
5. A while loop is used to count total characters of the given string.
6. It is initialized as i=0, checks the condition whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
7. Use an if condition to test if(str[i]!=’ ‘), if it is true,  The characters becomes characters + 1( characters = characters +1);
8. When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The words becomes words+1(words=words+1);
9. Finally, the program displays the total number of the words, characters and Space of the given string

Count word, characters and space using do-while loop

The program allows the user to enter a String and then it counts and display the total number of words, character and Space of the given string using do-while loop in C programing language

Program 3

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char str[100];
    int i;
    int words=1,characters=0,space=0;
    printf("Please enter the string \n");
    gets(str); //count characters of a string wit out space

    i=0;
    do{

            if(str[i]!=' '){ // checl characters
                characters++;
            }
             else if(str[i]==' ' || str[i] != '\n' || str[i] != '\t'){
                words++; //check words
            }
            i++;
    }while(str[i] != '\0');
printf("\nTotal words: %d ",words); //display total number of words
printf("\nTotal characters: %d",characters); //display total number of characters
printf("\nSpace: %d ",(words-1)); //display total number of space
getch();
    return 0;
}

When the above code is executed, it produces the following result

Please enter the string
Learn C basic tutorials code for coding

Total words: 7
Total characters: 33
Space: 6

Approach

1. Declare a Character array as char str[100];
2. Declare and initialize integer variables as words=1,space=0,caracters=0;
   
3. The user asked to enter a string
4. The given string is stored in the variable str;
5. A do-while loop is used to count total characters of the given string.
6. It is initialized as i=0, checks the condition whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
7. Use an if condition to test if(str[i]!=’ ‘), if it is true,  The characters becomes characters + 1( characters = characters +1);
8. When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The words becomes words+1(words=words+1);
9. Finally, the program displays the total number of the words, characters and Space of the given string

Suggested for you

for loop in C language

while loop in C language

do-while loop in C  language

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