C++ code to subtract two integer using Bitwise operator

C++ code to subtract two integer using Bitwise operator

In this article, we will discuss the concept of the C++ code to subtract two integer using Bitwise operator

In this post, we are going to learn how to  write a program to find the subtraction of two numbers using Bitwise operator in C++ programming language

Code to find the subtraction of  two numbers 

Subtract two integer using Bitwise operator

The program allow the user to enter two integers and then calculates subtraction of given  numbers using  Bitwise operator in C++ language

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int a,b,num1,num2;
//variable declaration
    cout<<"Enter first number: \n";
//Ask input from the user
    cin>>num1;
//Store the value in the num1 variable
    cout<<"Enter second number: \n";
//Ask input from the user
    cin>>num2;
//Store the value in the num2 variable
    a=num1; //Assign the value of num1 to variable a
    b=num2;  //Assign the value of num2 to variable b

    while (num2!= 0)//Calculate subtraction of the numbers using bitwise operator
    {
        int count=(~num1) & num2;
        num1=num1^num2;
        num2=count<<1;
    }
    cout<<"Subtraction of two numbers "<<a<<" and "<<b<<" is: "<<num1;
//Display result on the screen
getch();
    return 0;
}

When the above code is executed , it produces the following result

Case 1

Enter first number: 100
Enter second number: 45
Subtraction of two numbers 100 and 45 is: 55

Case 2

Enter first number: 20
Enter second number: 40
Subtraction of two numbers 20 and 40 is: -20

Subtract two integer using Bitwise operator-using function

The program allow the user to enter two integers and then calculates subtraction of given  numbers using  Bitwise operator in C++ language

Program 2

#include <iostream>
#include <conio.h>
using namespace std;
int sub(int,int);
int main()
{
    int num1,num2,ans;
    cout<<"Enter two numbers: \n";
    cin>>num1>>num2;
    ans=sub(num1,num2);//Calling the function
    cout<<"Subtraction of "<<num1<<" and "<<num2<<" is "<<ans;
    getch();
    return 0;
}
int sub(int x, int y){//function definition
  while(y!=0){
    int carry=(~x) & y;
    x=x^y;
    y=carry<<1;
  }
  return x;
}

When the above code is executed , it produces the following result

Case 1

Enter two numbers:
1200
700
Subtraction of 1200 and 700 is: 500

Case 2

Enter two numbers:
700
1200
Subtraction of 700 and 1200 is: -500

Suggested for you

Operator in C++ language

Data type in C++ language

Variable in C++ language

if statements in C++ language

Similar post

Subtract two numbers in  C++  language

Subtract two numbers using function in C++ language

Subtract two numbers using recursion in C++ language

Find sum of two numbers in C++

Find sum of two numbers in C++ using recursion

Find sum of two numbers in C++ without Arithmetic operator

Find sum of natural numbers in C++ language

Find sum of natural numbers in C++ language using recursion