• On April 29, 2020
• By Karmehavannan
• 0 Comment
• Categories: String
• Tags: C++ programs, Cpp language

C++ code to Count Alphabets, Numeric, Special character and Space in a string

C++ code to Count Alphabets, Numeric, Special character and Space

In this article, we will discuss the concept of the C++ code to Count Alphabets, Numeric, Special character and Space

In this post, we are going to learn how to count the total number of Alphabets, Numeric, Special character and Space of the given string in C++ programming language

 

C++ code to Count Alphabets, Numeric, Special character and Space in a string

Code to Count Alphabets, Numeric, Special character and Space using for loop

The program allows the user to enter a String and then it counts and display the total number of Alphabets, Numeric, Special character and Space of the given string using for loop in C++ programing language

Program 1

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;

int main()
{
    char str[100];
    int i;
    int Alphabets=0,num=0,special=0,space=0;
    cout<<"Please enter the string \n";
    gets(str); 
    for(i=0; str[i] != '\0'; i++){
        //check for Aphabets
            if((str[i]>='A' && str[i]<='Z') || (str[i]>='a' && str[i]<='z')) {  //check Alphabets
                Alphabets++;
    }else if(str[i]>='0' && str[i]<='9') {  //check numbers
                num++;
    }

    else if(str[i]==' '){//ceck space
                space++;
    }
    else{
        special++;
    }
    }
    cout<<"\nAlphabet letters: "<<Alphabets;

    cout<<"\nnumbers: "<<num;
      cout<<"\nSpace: "<<space;
    cout<<"\nSpecial characters: "<<special;
    getch();
    return 0;
}

When the above code is executed, it produces te following result

Pleases  enter the string
Code 4 you:code4coding.com

Alphabet letters: 20
Numbers: 2
Space: 2
Special characters: 2

Approach

1. Declare a Character array as char str[100];
2. Declare and initialize integer variables as Alphabets=0,num=0,space=0,Special=0;
   
3. The user asked to enter a string
4. The given string is stored in the variable str;
5. A for loop is used to count every total of the given string.
6. It is initialized as i=0, checks the condition whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
7. Use an if condition to test if((str[i]>=’A’ && str[i]<=’Z’) || (str[i]>=’a’ && str[i]<=’z’)), if it is true,  The Alphabets becomes Alphabets + 1( Alphabets = Alphabets +1);
8. When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The num becomes num+1(num=num+1);
9. When it is false, control moves to the next else-if part and evaluates the test-expression of else-if. if it is true The space becomes space+1(space=space+1);
10. When it is false, control moves to the else part and executes the else part statements. the special becomes special+1
11. Finally, the program displays the total number of the Alphabets, Numeric, Special character and Space of the given string

 

Code to Count Alphabets, Numeric, Special character and Space using while loop

The program allows the user to enter a String and then it counts and display the total number of Alphabets, Numeric, Special character and Space of the given string using While loop in C++ programing language

Program 2

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;

int main()
{
    char str[100];
    int i;
    int Alphabets=0,num=0,special=0,space=0;
    cout<<"Please enter the string \n";
    gets(str);
    i=0;
    while(str[i] != '\0'){
        //check for Alphabets
            if((str[i]>='A' && str[i]<='Z') || (str[i]>='a' && str[i]<='z')) {
                Alphabets++;
    }else if(str[i]>='0' && str[i]<='9') { //check numeric
                num++;
    }

    else if(str[i]==' '){ //check space
                space++;
    }
    else{
        special++;  //find special
    }
    i++;
    }
    cout<<"\nAlphabets letters: "<<Alphabets;

    cout<<"\nnumbers: "<<num;
      cout<<"\nSpace: "<<space;
    cout<<"\nSpecial characters: "<<special;
    getch();
    return 0;
}

When the above code is executed, it produces te following result

Pleases  enter the string
Basic program:code4coding.com


Alphabet letters: 25
Numbers: 1
Space: 1
Special characters: 2

 

Approach

1. Declare a Character array as char str[100];
2. Declare and initialize integer variables as Alphabets=0,num=0,space=0,Special=0;
   
3. The user asked to enter a string
4. The given string is stored in the variable str;
5. A while loop is used to count every total of the given string.
6. It is initialized as i=0, checks the condition whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
7. Use an if condition to test if((str[i]>=’A’ && str[i]<=’Z’) || (str[i]>=’a’ && str[i]<=’z’)), if it is true,  The Alphabets becomes Alphabets + 1( Alphabets = Alphabets +1);
8. When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The num becomes num+1(num=num+1);
9. When it is false, control moves to the next else-if part and evaluates the test-expression of else-if. if it is true The space becomes space+1(space=space+1);
10. When it is false, control moves to the else part and executes the else part statements. the special becomes special+1
11. Finally, the program displays the total number of the Alphabets, Numeric, Special character and Space of the given string

 

Code to Count Alphabets, Numeric, Special character and Space using do-while loop

The program allows the user to enter a String and then it counts and display the total number of Alphabets, Numeric, Special character and Space of the given string using do-while loop in C++ programing language

Program 3

#include <iostream>
#include <conio.h>
#include <stdio.h>
using namespace std;

int main()
{
    char str[100];
    int i;
    int Alphabets=0,num=0,special=0,space=0;
    cout<<"Please enter the string \n";
    gets(str);
    i=0;
  do{
        //check Alphabets
            if((str[i]>='A' && str[i]<='Z') || (str[i]>='a' && str[i]<='z')) {
                Alphabets++;
    }else if(str[i]>='0' && str[i]<='9') {  //Check numeric
                num++;
    }

    else if(str[i]==' '){  //check space
                space++;
    }
    else{
        special++;  //find special
    }
    i++;
    }  while(str[i] != '\0');
    cout<<"\nAlphabets letters: "<<Alphabets;

    cout<<"\nnumbers: "<<num;
      cout<<"\nSpace: "<<space;
    cout<<"\nSpecial characters: "<<special;
    getch();
    return 0;
}

When the above code is executed, it produces te following result

Pleases  enter the string
Basic program:code4coding.com


Alphabet letters: 26
Numbers: 2
Space: 2
Special characters: 2

 

Approach

1. Declare a Character array as char str[100];
2. Declare and initialize integer variables as Alphabets=0,num=0,space=0,Special=0;
   
3. The user asked to enter a string
4. The given string is stored in the variable str;
5. A do-while loop is used to count every total of the given string.
6. It is initialized as i=0, checks the condition whether str[i] != ‘\0’; and executes the loop until the given condition becomes true
7. Use an if condition to test if((str[i]>=’A’ && str[i]<=’Z’) || (str[i]>=’a’ && str[i]<=’z’)), if it is true,  The Alphabets becomes Alphabets + 1( Alphabets = Alphabets +1);
8. When it is false, control moves to the else-if part and evaluates the test-expression of else-if. if it is true The num becomes num+1(num=num+1);
9. When it is false, control moves to the next else-if part and evaluates the test-expression of else-if. if it is true The space becomes space+1(space=space+1);
10. When it is false, control moves to the else part and executes the else part statements. the special becomes special+1
11. Finally, the program displays the total number of the Alphabets, Numeric, Special character and Space of the given string

 

 

Suggested for you

for loop in C++ language

while loop in C++ language

do-while loop in C++ language

 

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