C++ code to 5 ways to check whether the given integer is Even or Odd

C++ code to 5 ways to check whether the given integer is Even or Odd

In this tutorial, we will discuss the concept of  C++ code to 5 ways to check whether the given integer is Even or Odd

In this post, we are going to learn how to check whether the given integer is even or odd using 5 different ways in C++ programming language.

 

C++ code to 5 ways to Check Even or Odd

Using Modular operator

Program 1

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
     cout << "Enter a integer number" << endl;
    cin>>num;//takes input from user
    //using modular operator
    if(num%2==0){
  cout<<num<<" is a Even number ";
}else{
 cout<<num<<" is a odd number ";
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter a integer number
500
500 is a Even number

case 2

Enter a integer number
301
301 is a odd number

This program allows the user to enter a number and then, the program will check and display the odd or even numbers from the given number(entered by the user) using modular operator

 

Using the division operator

Program 2

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
     cout << "Enter the integer number" << endl;
    cin>>num;//takes input from user
    //using division operator
    if((num/2)*2==num){
  cout<<num<<" is a Even number ";
}else{
 cout<<num<<" is a odd number ";
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter a integer number
300
300 is a Even number

case 2

Enter a integer number
211
211 is a odd number

This program allows the user to enter a number and then, the program will check and display the odd or even numbers from the given number(entered by the user) using division operator

 

Using Bitwise AND operator

Program 3

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
     cout << "Enter the integer number" << endl;
    cin>>num;//takes input from user
    //using bitwise AND operator
    if((num&1)==0){
  cout<<num<<" is a Even number ";
}else{
 cout<<num<<" is a odd number ";
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter a integer number
788
788 is a Even number

case 2

Enter a integer number
555
555 is a odd number

This program allows the user to enter a number and then, the program will check and display the odd or even numbers from the given number(entered by the user) using bitwise AND operator

 

Using shift operator

Program 4

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
     cout << "Enter the integer number" << endl;
    cin>>num;//takes input from user
    //using shift operator
    if(((num>>1)<<1)==num){
  cout<<num<<" is a Even number ";
}else{
 cout<<num<<" is a odd number ";
}
getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter a integer number
1000
1000 is a Even number

case 2

Enter a integer number
999
999 is a odd number

This program allows the user to enter a number and then, the program will check and display the odd or even numbers from the given number(entered by the user) using shift operator

 

 

Using ternary operator

Program 5

#include <iostream>
#include <conio.h>
using namespace std;

int main()
{
    int num;
     cout << "Enter the integer number" << endl;
    cin>>num;//takes input from user
    //using ternary operator
    (num%2==0) ? cout<<num<<" is even.":cout<<num<<" is odd.";
getch();
    return 0;
}

When the above code is executed, it produces the following results

case 1

Enter a integer number
50
50 is Even

case 2

Enter a integer number
51
51 is odd

This program allows the user to enter a number and then, the program will check and display the odd or even numbers from the given number(entered by the user) using the ternary operator

 

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